Answer:
0.56 atm
Explanation:
First of all, we need to find the number of moles of the gas.
We know that
m = 1.00 g is the mass of the gas
is the molar mass of the carbon dioxide
So, the number of moles of the gas is
Now we can find the pressure of the gas by using the ideal gas equation:
where
p is the pressure
is the volume
n = 0.023 mol is the number of moles
is the gas constant
is the temperature of the gas
Solving the equation for p, we find
And since we have
the pressure in atmospheres is
The trickiest part of this problem was making sure where the Yakima Valley is.
OK so it's generally around the city of the same name in Washington State.
Just for a place to work with, I picked the Yakima Valley Junior College, at the
corner of W Nob Hill Blvd and S16th Ave in Yakima. The latitude in the middle
of that intersection is 46.585° North. <u>That's</u> the number we need.
Here's how I would do it:
-- The altitude of the due-south point on the celestial equator is always
(90° - latitude), no matter what the date or time of day.
-- The highest above the celestial equator that the ecliptic ever gets
is about 23.5°.
-- The mean inclination of the moon's orbit to the ecliptic is 5.14°, so
that's the highest above the ecliptic that the moon can ever appear
in the sky.
This sets the limit of the highest in the sky that the moon can ever appear.
90° - 46.585° + 23.5° + 5.14° = 72.1° above the horizon .
That doesn't happen regularly. It would depend on everything coming
together at the same time ... the moon happens to be at the point in its
orbit that's 5.14° above ==> (the point on the ecliptic that's 23.5° above
the celestial equator).
Depending on the time of year, that can be any time of the day or night.
The most striking combination is at midnight, within a day or two of the
Winter solstice, when the moon happens to be full.
In general, the Full Moon closest to the Winter solstice is going to be
the moon highest in the sky. Then it's going to be somewhere near
67° above the horizon at midnight.
Answer:
The magnitude of change in momentum is (2mv).
Explanation:
The momentum of an object is given by the product of mass and velocity with which it is moving.
Let the mass of ball is m. A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it struck the wall.
Initial speed of the ball is v and final speed, when it rebounds, is (-v). The change in momentum is given by :
p = final momentum - initial momentum
So, the magnitude of change in momentum is (2mv).
<h2>Energy remains constant </h2>
Explanation:
Thermodynamic Laws -
- The primary law, otherwise called the Law of Conservation of Energy, expresses that energy remains constant in the overall reaction, it is not created or destroyed.
- The second law of thermodynamics expresses that the entropy increases. after the completion of the reaction of any isolated system
- The third law of thermodynamics expresses that as the temperature reaches towards an absolute zero point the entropy of a system becomes constant.
Standard Electronic potential -
- The standard reduction potential may be defined as the tendency of a chemical species or the reactants to get into its reduced form after the overall reaction.
- It is estimated at volts.
- The more is the positive potential the more is the reduction of the chemical species
Aerobic grow is much more efficient at making ATP because of the presence of oxygen the cycles in the respiration are carried out at an efficient rate which forces the cell to undergo a much large amount of ATP production.
