The convection currents in the student’s model different from the convection currents in Earth’s atmosphere and oceans, The sun. Because heats is obtained from the sun, is transferred to the Earth's atmosphere and seas.
<h3 /><h3>What is an experiment?</h3>
An experiment is a technique used to prove or disprove a theory, or to test the efficacy or probability of something that has never been done before.
The burner underneath the kettle is the source of heat in this experiment. On Earth, however, this is not the case since the source of heat is the Sun, which heats us from above rather than below.
Convection currents continue to flow in the same direction because when the sun heats air particles on the Earth's surface,
They ascend, but cool as they continue to climb. This causes them to descend, where they are heated up once more.
Hence,heats is obtained from the sun, is transferred to the Earth's atmosphere and seas.
To learn more about the experiment, refer to the link;
brainly.com/question/11256472
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Answer:
Explanation:
L 1: front radius 950 mm, rear radius 2700 mm, refractive index 1.528;
We shall use lens maker's formula , that is
1/f = (μ-1) ( 1/R₁ - 1/R₂) , μ is refractive index of the lens , R₁ and R₂ are radius of curvature of front and rear curved surface.
1/f₁ = (1.528-1)( 1/950 + 1/2700)
f₁ = 1331 mm
L2: front radius 535 mm, rear radius 500 mm, refractive index 1.550.
1/f₂ = (1.550-1)( 1/535 + 1/500)
f₂ = 470 mm
largest angular magnification possible
= f₁ /f₂
= 1331 / 470
= 2.83 ( approx )
Length between two lenses
=1331 +470
= 1801 mm
= 1.8 m Ans
Answer:21.97 m/s
Explanation:
Mass of truck ![m_T=2000 kg](https://tex.z-dn.net/?f=m_T%3D2000%20kg)
Velocity of truck ![v_c=4 m/s](https://tex.z-dn.net/?f=v_c%3D4%20m%2Fs)
Mass of car ![m_c=1000 kg](https://tex.z-dn.net/?f=m_c%3D1000%20kg)
let
be the car velocity and u be the velocity of combined system after collision at angle of ![20^{\circ}](https://tex.z-dn.net/?f=20%5E%7B%5Ccirc%7D)
Conserving momentum in east and North direction Respectively
In east Direction
-------1
In North direction
---------2
Divide 1 and 2 we get
![\frac{m_T\cdot v_T}{m_c\cdot v_c}=\frac{(m_c+m_T)u\sin 20}{(m_c+m_T)u\cos 20}](https://tex.z-dn.net/?f=%5Cfrac%7Bm_T%5Ccdot%20v_T%7D%7Bm_c%5Ccdot%20v_c%7D%3D%5Cfrac%7B%28m_c%2Bm_T%29u%5Csin%2020%7D%7B%28m_c%2Bm_T%29u%5Ccos%2020%7D)
![v_c=\frac{m_T\cdot v_T}{m_c\cdot \tan 20}](https://tex.z-dn.net/?f=v_c%3D%5Cfrac%7Bm_T%5Ccdot%20v_T%7D%7Bm_c%5Ccdot%20%5Ctan%2020%7D)
![v_c=\frac{2000}{1000}\times \frac{4}{\tan 20}](https://tex.z-dn.net/?f=v_c%3D%5Cfrac%7B2000%7D%7B1000%7D%5Ctimes%20%5Cfrac%7B4%7D%7B%5Ctan%2020%7D)
![v_c=21.97 m/s](https://tex.z-dn.net/?f=v_c%3D21.97%20m%2Fs)
Ideal Gas Law is, pV = NkbT
<span>Therefore, p/t = Nkb/V which is
equal to the constant</span>
We need to convert the given temperature to Kelvin. We need to add 273 to
have the Kelvin of the temperature from Celsius.
T1= 20 + 273 = 293 K
T2= 120 + 273 = 393 K
With this we have the pressure ration of 393/293.
So,F120 = 1.34 APa
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