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Romashka-Z-Leto [24]
3 years ago
9

What is the mass/volume percent concentration of 2.75g of K2SO2 dissloved in 350.0 ml of solution

Chemistry
1 answer:
nataly862011 [7]3 years ago
7 0

Answer:7682.08 grams

Explanation:

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If a radioisotope has a half-life of 4 years, how much remains of a starting amount of 40 grams after 16 years have passed?
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1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride ? atoms of boron.
maks197457 [2]

Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in  of boron trifluoride? moles of fluorine.​

Explanation:

The molecular formula of boron trifluoride is BF_3.

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- 6.023x10^2^3 atoms.

Then, 2.20 moles of boron has

-=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\\=13.25x10^2^3 atoms

2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\\=0.0888mol

One mole of boron trifluoride has three moles of fluorine atoms.

Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

=0.266mol of fluorine atoms.

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