Moles of Na_2O
- Given mass/Molar mass
- 35/62
- 0.56mol
2 mols Na_2O produces 1 mol sodium carbonate.
1 mol sodium oxide produces 0.5mol sodium carbonate
Moles of sodium carbonate
Molar mass
- 2(23)+12+3(16)
- 46+12+48
- 106g/mol
Mass
Answer:
both are solids, both are somewhat pliable
Answer:
I hope this helps you! :)
Explanation:
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W=0.360
p=1.18g/mL
pH=2.12
v=14.0 L
M(HCl)=36.46 g/mol
v₀-?
1) pH=-lg[H⁺]
[H⁺]=c(HCl)=10^(-pH)
n(HCl)=v[H⁺]=v*10^(-pH)
2) n(HCl)=m(HCl)/M(HCl)=wv₀p/M(HCl)
3) v*10^(-pH)=wv₀p/M(HCl)
v₀=v*10^(-pH)M(HCl)/(wp)
v₀=14.0*10^(2.12)*36.46/(0.360*1.18)=9.115 mL
Approximately 9.1 mL of concentrated solution required.
First, we determine how many electrons can each subshell hold:
s can hold 2 electrons
p can hold 6 electrons
d can hold 10 electrons
f can hold 14 electrons
Second, we start distributing the 10 electrons on the orbitals of subshells based on the arrangement shown in the question :
1s will hold 2 electrons
2s will hold 2 electrons
2p will hold 6 electrons
All other orbitals will will hold zero electrons as the 10 were distributed among the first 2
Answer: 1s: 2
2s: 2
2p: 6
<span> 3s: 0
3p: 0
4s: 0
3d: 0
4p: 0
5s: 0</span>