The type of the bond is present Na₃PO₄ is the ionic bond. the Na₃PO₄ is the ionic compound. yes the Na₃PO₄ is the polyatomic ion.
The Na₃PO₄ is Na⁺ and PO₄³⁻. the phosphorus is the non metal and the oxygen atom is the non metal. the non meta and non meta form the covalent or molecular bond. the bond between the PO₄³⁻ bond is the covalent bond but the overall present in the Na₃PO₄ is the ionic bond . the bons in between the Na⁺ and PO₄³⁻ is the the ionic bond. the PO₄³⁻ id the polyatomic ion .
The bond between the positively charged ion and the negatively charged ion are called as the ionic bond and the compound form is the ionic compound.
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Answer:
C₃H₄O₄
Explanation:
In order to get the empirical formula of a compound, we have to follow a series of steps.
Step 1: Divide the percent by mass of each element by its atomic mass.
C: 34.6/12.01 = 2.88
H: 3.9/1.01 = 3.86
O: 61.5/16.00 = 3.84
Step 2: Divide all the numbers by the smallest one, i.e., 2.88
C: 2.88/2.88 = 1
H: 3.86/2.88 ≈ 1.34
O: 3.84/2.88 ≈ 1.33
Step 3: Multiply all the numbers by a number that makes all of them integer
C: 1 × 3 = 3
H: 1.34 × 3 = 4
O: 1.33 × 3 = 4
The empirical formula is C₃H₄O₄.
<span>1.) a. 20 ÷ 4 ? means ? × 4 = 20 </span>→ replace ? with 5.<span>
b. 2,725 ÷ 5 ? means ? × 5 = 2,725 </span>→ replace ? with 545<span>
c. ? ÷ 5 = 0 </span>→ replace ? with 0.
2) 1,475 / 25 = 59
They used 59 boxes for this year.
3) 18 per haircut ; 70 per perm
4,608 = 18h + 70(36)
4,608 - 2,520 = 18h
2,088 = 18h
2,088/18 = h
116 = h
Grace did 116 haircuts.
4) 575 + 13(118) = 575 + 1,534 = 2,109 total expense.
5) 2,240 miles / 320 miles = 7 tanks of gas used.
7 tanks * 39 = 273 cost of the gas used.
Answer is: empirical formula is H₄N₂O₂.
m(unknown compound) = 8,5 g.
m(N₂) = 2,37 g.m(H₂O) = 3,04 g.
n(N₂) = m(N₂) ÷ M(N₂).
n(N₂) = 2,37 g ÷ 28 g/mol.
n(N₂) = 0,0846 mol.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 3,04 g ÷ 18 g/mol.
n(H₂O) = 0,168 mol.
n(H₂O) : n(N₂) = 0,168 mol : 0,0846 mol.
n(H₂O) : n(N₂) = 2 : 1.
Compound has four hydrogen, two oxygen and two oxygen.
Answer:
D. The higher energy chair conformation contains two axial methyl groups.
Explanation:
The diaxial trans-1,4-dimethylcyclohexane has the highest energy (the least stable) and the diequatorial chair conformation has the lowest energy (the most stable).
The diaxial conformation has a higher energy due to the interaction between the methyl groups.
