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Katyanochek1 [597]
3 years ago
12

elect the correct answer. The elements beryllium, calcium, and strontium are all in group 2. What is the correct relationship of

these elements regarding their ionization energy? A. Ca < Be < Sr B. Sr < Be < Ca C. Be < Ca < Sr D. Sr < Ca < Be E. Ca < Sr < Be

Chemistry
1 answer:
deff fn [24]3 years ago
3 0

Answer:

D. Sr < Ca < Be  

Step-by-step explanation:

<em>Ionization energ</em>y decreases from top to bottom within a Group, because the valence electrons are further from the nucleus and therefore easier to remove.

Thus, <em>Sr has the lowest</em> ionization energy and <em>Be the highes</em>t.

The correct order is Sr < Ca < Be.

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Acids and bases can neutralize each other in double displacement reactions. For example, if hydrogen chloride (a strong acid, HC
scoray [572]

Answer:

The answer to your question is    HCl  +  NaOH   ⇒   NaCl  +  H₂O

Explanation:

Data

Double displacement reaction

Balanced chemical reaction

               HCl  +  NaOH   ⇒   NaCl  +  H₂O

           Reactants           Elements                Products

                 1                  Chlorine (Cl)                    1

                 1                   Sodium (Na)                   1

                 2                 Hydrogen (H)                  2

                 1                   Oxygen (0)                      1

As we can see, the reaction is balanced and the coefficients of all reactants and products are 1, but the number is not written in a balanced reaction.

8 0
3 years ago
Drag each tile to the correct location on the image.
nikdorinn [45]

Answer:

[He]: 2s² 2p⁵.

[Ne]: 3s².

[Ar]: 4s² 3d¹⁰ 4p².

[Kr]: 5s² 4d¹⁰ 5p⁵.

[Xe]: 6s² 4f¹⁴ 5d¹⁰ 6p².

Explanation:

  • Noble elements are used as blocks in writing the electronic configuration of other elements as they are stable elements.

  • [He]:

He contains 2 electrons fill 1s (1s²).

So, [He] can be written before the electronic configuration of 2s² 2p⁵.

  • [Ne]:

Ne contains 10 electrons fill (1s² 2s² 2p⁶).

So, [Ne] can be written before the electronic configuration of 3s².

  • [Ar]:

Ar contains 18 electrons is configured as ([Ne] 3s² 3p⁶).

So, [Ar] can be written before the electronic configuration of 4s² 3d¹⁰ 4p².

  • [Kr]:

Kr contains 36 electrons is configured as ([Ar] 4s² 3d¹⁰ 4p⁶).

So, [Kr] can be written before the electronic configuration of 5s² 4d¹⁰ 5p⁵.

  • [Xe]:

Xe contains 54 electrons is configured as ([Kr] 5s² 4d¹⁰ 5p⁶).

So, [Xe] can be written before the electronic configuration of 6s² 4f¹⁴ 5d¹⁰ 6p².

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