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Maru [420]
3 years ago
6

Ground glass is a/an _______ material. a) softb) opaquec) translucentd) transparent​

Chemistry
2 answers:
pochemuha3 years ago
6 0

Answer:

Opaque Material

Monica [59]3 years ago
6 0

Answer:

A ground glass is translucent as it allows only partial light to pass through it and forms light shadows

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What is the acceleration of the ball if it has a mass of 1.5 kg and had a force of 45 N?
Tatiana [17]

Answer:

30

Explanation:

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3 years ago
A small diamond, which is made of pure carbon, contains too many carbon atoms to count individually. Which is closest to the num
8090 [49]

The correct answer is option C, 5.02 x 10²² carbon atoms

Atomic mass of C = 12 g/mol

According to Avogadro, 1 mole of C has 6.023 x 10²³C atoms

Now 1 mole of C is equal to 12 g

Therefore, 12 g of C = 6.023 x 10²³ C atoms

1 g of C = \frac{6.023 x 10^2^3}{12} C atoms = 5.02 x 10²² C atoms

7 0
3 years ago
Which of the following best explains what happens when the kinetic energy of particles in a liquid state increases?
klio [65]

They move fast enough to overcome the forces of attraction that hold them together, becoming a gas.

ITS THAT :)

5 0
3 years ago
Read 2 more answers
How fast is an electron travelling If it has a wavelength of 8.20 km?
Lemur [1.5K]

The electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

<h3>How to calculate velocity of an electron?</h3>

The velocity at which an electron travels can be calculated using the following formula:

λ = h/mv

Where;

  • H = Planck's constant
  • m = mass of electron
  • v = velocity of electron
  • λ = wavelength

  • Planck's constant (h) = 6.626 × 10−³⁴ J⋅s.
  • mass of electron (m) = 9.109 × 10−³¹ kg
  • wavelength = 8200m

8200 = 6.626×10−³⁴ / 9.109 × 10−³¹V

8200 = 7.3 × 10-⁴V

V = 8200 ÷ 7.3 × 10-⁴

V = 1.123 × 10⁷m/s

Therefore, the electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

Learn more about velocity at: brainly.com/question/13171879

#SPJ1

5 0
2 years ago
Formula of a copper (II)sulfate hydrate lab
s344n2d4d5 [400]

Answer:

Weigh the empty crucible, and then weigh into it between 2 g and 3 g of hydrated copper(II) sulphate. Record all weighings accurate to the nearest 0.01 g.

Support the crucible securely in the pipe-clay triangle on the tripod over the Bunsen burner.

Heat the crucible and contents, gently at first, over a medium Bunsen flame, so that the water of crystallisation is driven off steadily. The blue colour of the hydrated compound should gradually fade to the greyish-white of anhydrous copper(II) sulfate. Avoid over-heating, which may cause further decomposition, and stop heating immediately if the colour starts to blacken. If over-heated, toxic or corrosive fumes may be evolved. A total heating time of about 10 minutes should be enough.

Allow the crucible and contents to cool. The tongs may be used to move the hot crucible from the hot pipe-clay triangle onto the heat resistant mat where it should cool more rapidly.

Re-weigh the crucible and contents once cold.

Calculation:

Calculate the molar masses of H2O and CuSO4 (Relative atomic masses: H=1, O=16, S=32, Cu=64)

Calculate the mass of water driven off, and the mass of anhydrous copper(II) sulfate formed in your experiment

Calculate the number of moles of anhydrous copper(II) sulfate formed

Calculate the number of moles of water driven off

Calculate how many moles of water would have been driven off if 1 mole of anhydrous copper(II) sulfate had been formed

Write down the formula for hydrated copper(II) sulfate.

#*#*SHOW FULLSCREEN*#*#

Explanation:

7 0
3 years ago
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