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andrew11 [14]
4 years ago
5

How many atoms are in one mole of co2?

Chemistry
2 answers:
9966 [12]4 years ago
8 0
There are 3 atoms babe
BigorU [14]4 years ago
6 0

There are 3 atoms in 1 molecule of Co2.

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When the following equation is balanced, what is the coefficient for HBr?
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D.) Balanced equation is Zn + 2HBr - - - > ZnBr2 + H2.
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4 years ago
3. Identify the oxidizing agent in each of the fol-
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Answer:

Cu

Fe

Explanation:

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

a) Cu²⁺ (aq) + Mg(s) + Cu(s) + Mg²⁺(aq)

Copper is oxidizing agent it accept two electrons from magnesium and oxidize the Mg and itself get reduced.

b) Fe₂O₃(s) + 3CO(g) → 2Fe(l) + 3CO₂(g)​

In this reaction iron is oxidizing agent because iron itself reduced from +3 to 0.

5 0
3 years ago
Private land is generally used for _______. a. homes b. businesses c. factories d. all of the above Please select the best answe
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3 years ago
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Is Mg(CH3COO)2 soluble or insoluble
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Answer:

It is Soluble

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3 years ago
Suppose 12.0 g of carbon (c) reacts with 70.0 g of sulfur (s) to give 76.0 g of the compound carbon disulfide 1 c s 2 2 . In the
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Answer is: mass of unused sulfur is 5.87 grams.

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m(C) = 12.0 g; mass of carbon.

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n(C) = m(C) ÷ M(C).

n(C) = 12 g ÷ 12 g/mol.

n(C) = 1 mol; amount of substance.

n(S) = m(S) ÷ M(S).

n(S) = 70 g ÷ 32.065 g/mol.

n(S) = 2.183 mol.

From chemical reaction: n(C) : n₁(S) = 1 : 2.

n₁(S) = 1 mol · 2 = 2 mol.

Δn(S) = n(S) - n₁(S).

Δn(S) = 2.183 mol - 2 mol.

Δn(S) = 0.183 mol; amount of unused sulfur.

Δm(S) = 0.183 mol · 32.065 g/mol.

Δm(S) = 5.87 g.

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