Which structure is the final layer for oxygen to encounter before diffusing into the bloodstream?

1 answer:

8 0

C. capillary Wall 'CAuse first the oxygen goes into your alveolus and then pass through the capillary wall so hemoglobine can carry it to other tissues

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If a frog cell with 2n = 26 undergoes mitosis one of the daughter cells would have _____ chromosomes and if that frog cell with

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Answer:

C.) 26 - 13

Explanation:

During mitosis, DNA is replicated during the S phase so that when the cell divides the daughter cells will have the same number of chromosomes that the parent cell had.

DNA replication also occurs during meiosis, but the cell divides twice, so the daughter cells will have half the number of chromosomes that the parent cell had. This is because the daughter cells are sex cells, which combine with another sex cell (either an egg or a sperm) to form one cell with a combined chromosome number.

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Which of the following is example of a scientific model?

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Answer

solar system, a globe of earth

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Cilia and flagella are similar in that they are both made of micro tubes<br> True or false

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I belive it is False

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Autotroph is to producer as heterotroph is to

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Autotroph is to producer as Hetrotroph is to consumer

Autotrophs make their own food, which makes them producers
While Hetrotrophs cannot make their own food, and must obtain it from another source, making them consumers

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A man with normal vision marries a color-blind woman. Red-green color blindness is an X- linked recessive disorder. They have a

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Answer: The probability is 100%.

Explanation: The chromosome X is related to gender. A man carries two different chromosomes (XY) and a woman carries two similar chromosomes (XX). The offspring of a couple will inherited:

If it is a boy, he inherites the chromosome Y from his father and X from his mother;
If it a girl, she inherites X from her father and X from her mother;

In the question, the woman is color-blind, which means she carries the recessive alleles: $X^{d}X^{d}$

The man, on the other hand, is normal, so his X-linked genotype will be: $X^{D}Y$ .

Now, since they have a daughter, she inherited her double X from each of her parents, which means she inherited one $X^{d}$ from her mother and one $X^{D}$ from her father.

So, the daughter's genotype can only be heterozygotic $X^{D}$ $X^{d}$ in other words, the probability is 100%.

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