Question

A biker rides on an upward-sloped road inclined at a 15.0° angle with the horizontal. If he moves at a constant speed of 2.0 meters/second for 60 seconds, what is the magnitude of his horizontal displacement?
3 meters

116 meters

60 meters

130 meters


|

|

| v=2.0m/s

|

|______0=15 degrees

v2

Answer 1

With total velocity $v=2.0\,\dfrac{\mathrm m}{\mathrm s}$, the horizontal component of velocity is

$v_x=\left(2.0\,\dfrac{\mathrm m}{\mathrm s}\right)\cos15.0^\circ\approx1.93\,\dfrac{\mathrm m}{\mathrm s}$

Then the horizontal displacement over the first minute is

$s_x=\left(1.93\,\dfrac{\mathrm m}{\mathrm s}\right)(60\,\mathrm s)\approx116\,\mathrm m$

Answer 2

B. 116 meters for plato users :)