Answer: vf = 51 m/s
d = 112 m
Explanation: Solution attached:
To find vf we use acceleration equation:
a = vf - vi / t
Derive to find vf
vf = at + vi
Substitute the values
vf = 3.5 m/s² ( 8.0 s) + 23 m/s
= 51 m/s
To solve for distance we use
d = (∆v)² / 2a
= (51 m/s - 23 m/s )² / 2 ( 3.5 m/s²)
= (28 m/s)² / 7 m/s²
= 784 m/s / 7 m/s²
= 112 m
I think the correct answer from the choices listed above is option A. Wave motion is a movement of energy through space or a medium . Some waves are visible light waves, heat waves, sound waves and the like. Hope this answers the question.
Answer:
Since this is a linear equation
y = m x + b or
U = m F + b is a linear equation
when ΔF = (212 - 32) = 180
and ΔU = (60 - (-15)) = 75
m = 75 / 180 = 2.4 if converting F to U and a = .417
U = .417 F + b
If F = 32 then U = -15 and
-15 = .417 * 32 + b
b = -15 - 13.3 = -28.3 and our equation becomes
U = .417 F - 28.3
Check: let F = 212
U = .417 * 212 - 28.3 = 60 as it should
As per the question a frog jumps 5 m towards east.
Frog again jumps 2 m north.
Let the displacement along east is denoted by vector A and the displacement towards north is denoted as vector B.
Hence magnitude of A = 5 m
Magnitude of B = 2 m
We are asked to calculate the total displacement.
Here the angle between them is 90 degree as A is towards east and B is towards north.
As per parallelogram law of vector addition,the magnitude of total displacement [R] will be-
[cos90= 0]
[ans]
Answer:
What is observed that connects radio emissions in the galactic nucleus with the emissions in the halo or radio lobes? There is a jet of matter coming out of the nucleus, which often points toward the lobes.