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Orlov [11]
3 years ago
14

Air enters a compressor with a pressure of 14.7 lbf/in.2 , a temperature of 70F, and a volumetric flow rate of 40 ft3 /s. Air ex

its the compressor at 50 lbf/in.2 and 190F. Heat transfer from the compressor to its surroundings occurs at a rate of 20.5 Btu per lb of air flowing. Determine the compressor power, in hp, for steady-state operation.

Physics
1 answer:
disa [49]3 years ago
3 0

Answer:

210 hp

Explanation:

See attached picture.

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A 60 W lightbulb has a resistance of 240 ohms. At the operating temperature of the tungsten filament, the resistivity is approxi
irakobra [83]

Answer:

L = 6.032 m

Explanation:

The resistance of a wire is given by

      R = ρ L / A

done ρ is the resistivity of matter, L is the length and A is the area

      L = R A /ρ

the area of ​​a circle is

    A = π r² = π d² / 4

    L = R π d² / 4ρ

in the problem they indicate the resistance of 240 Ω, the diameter of 0.040 mm and the resistivity of 5 10⁻⁷ Ω / m

Let's reduce the diameter to SI units

   d = 0.040 mm (1 m / 1000 mm) = 4 10⁻⁵ m

let's calculate

     L = 240 π (4 10⁻⁵) 2 / (4 5 10⁻⁷)

     L = 6.0319 m

     L = 6.032 m

6 0
3 years ago
Which of these is NOT a physical property?
m_a_m_a [10]
I believe the answer is chemical reactivity because: Characteristics such as melting point, boiling point, density, solubility, color, odor, etc. are physical properties.
8 0
2 years ago
1.
ale4655 [162]

Answer:

5.0 atm

Explanation:

P₁V₁=P₂V₂

P₁V₁/V₂=P₂

(1)(2.5)/(0•50)=P₂

P₂=5

Pressure is now 5.0 atm

8 0
3 years ago
What's 5 and 6? Physics
andre [41]
5) 204 meters 
6)
A) 150 miles
B)241 km
4 0
3 years ago
Arocket launches at an angle of 33.6 degrees from the horizontal at a
babymother [125]

Answer:

Y component = 32.37

Explanation:

Given:

Angle of projection of the rocket is, \theta=33.6

Initial velocity of the rocket is, u=58.5

A vector at an angle \theta with the horizontal can be resolved into mutually perpendicular components; one along the horizontal direction and the other along the vertical direction.

If a vector 'A' makes angle \theta with the horizontal, then the horizontal and vertical components are given as:

A_x=A\cos \theta(\textrm{Horizontal or X component})\\A_y=A\sin \theta(\textrm{Vertical or Y component})

Here, as the velocity is a vector quantity and makes an angle of 33.6 with the horizontal, its Y component is given as:

u_y=u\sin \theta

Plug in the given values and solve for u_y. This gives,

u_y=(58.5)(\sin 33.6)\\u_y=58.5\times 0.55339\\u_y=32.373\approx32.37(\textrm{Rounded to two decimal places})

Therefore, the Y component of initial velocity is 32.37.

4 0
3 years ago
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