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3 years ago

13

in a combustion reaction at standard temperature and standard pressure,C2H6 reacts completely with 17.9 L of oxygen. what mass i

n grams of water vapor is produced?

1 answer:

Liono4ka [1.6K]3 years ago

8 0

Answer: 12.3 g H2O

Explanation: solution attached:

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Everyone who is thin is in shape. A. True B. False

MAVERICK [17]

Answer:

false; one could be in thin shape but thay doesnt always mean they are healthy, or fit...there is always a chance there can be malnutrition or they have a good metabolism, but to be in shape, there should be a good balance of fat and muscle in the body

7 0

3 years ago

13. In the wintertime, there is<br> food <br> sunlight (energy), so producers are making

kumpel [21]

Answer: shelter

Explanation:

Producers make food for the rest of the ecosystem through the process of photosynthesis, where the energy of the sun is used to convert carbon dioxide and water into glucose.

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3 years ago

The density of concentrated nitric acid (HNO3) is 1.413 g/mL. What volume in liters would be occupied by a mass of 47.2 g?

DerKrebs [107]

Answer:

The volume that a mass of 47.2 g would occupy is 0.0334 L

Explanation:

Density is the property that matter, whether solid, liquid or gas, has to compress into a given space. Density is defined as the amount of mass it has per unit volume, that is, the ratio between the mass of a body and the volume it occupies:

$Density=\frac{mass}{volume}$

This indicates that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

In this case:

density= 1.413 g/mL
mass= 47.2 g
volume=?

Replacing:

$1.413 \frac{g}{mL}=\frac{47.2 g}{volume}$

Solving:

$volume=\frac{47.2 g}{1.413\frac{g}{mL} }$

volume=33.40 mL

Being 1,000 mL= 1 L:

volume= 0.0334 L

<u><em> The volume that a mass of 47.2 g would occupy is 0.0334 L</em></u>

4 0

4 years ago

If you have 100 grams of a chemical with a half-life of 8 days, then how much will you have after 40 days?

dedylja [7]

Answer:

option d = 3.125 g

Explanation:

Given data:

Mass of chemical = 100 g

Half life = 8 days

mass left after 40 days = ?

Solution:

First of all we will calculate the total half life's,

half life's = T (elapsed) / T half life

half life's = 40 / 8 = 5

starting mass = 100 g

half life's 1 2 3 4 5

Mass 100/2 50/2 25/2 12.5/2 6.25/2

50 g 25 g 12.5 g 6.25 g 3.125 g

8 0

4 years ago

How much energy is evolved during the reaction of 51.2 g of al, according to the reaction below? assume that there is excess fe2

sesenic [268]

Answer : The amount of energy evolved during the reaction is, $-807.696KJ$ .

Solution : Given,

$\Delta H=-852KJ$

Mass of Al = 51.2 g

Molar mass of Al = 27 g/mole

First we have to calculate the moles of Al.

$\text{ Moles of Al}=\frac{\text{ Mass of Al}}{\text{ Molar mass of Al}}=\frac{51.2g}{27g/mole}=1.896moles$

The balanced combustion reaction is,

$Fe_2O_3+2Al\rightarrow Al_2O_3+2Fe$

From the given reaction, we conclude that

As, 2 moles of Al evolved energy = $-852KJ$

So, 1.896 moles of Al evolved energy = $\frac{-852KJ}{2moles}\times 1.896moles=-807.696KJ$

Therefore, the amount of energy evolved during the reaction is, $-807.696KJ$ .

8 0

3 years ago