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antoniya [11.8K]
3 years ago
12

10.0 mL of 3.0 M sulfuric acid has been added to 50.0 mL of water.

Chemistry
1 answer:
Cloud [144]3 years ago
3 0

Answer:

the new concentration is 0.60M

Explanation:

The computation of the new concentration is shown below;

We know that

M1V1=M2V2

(3.0M) (10.0 mL) = M2 (50.0mL)

30 = M2 (50.0mL)

So, M2 = 0.60 M

Hence, the new concentration is 0.60M

The same is considered and relevant

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A strong acid- strong base titration is performed using a phenolphthalein indicator. Phenolphtalein is chosen because it changes color in a pH range between 8.3 – 10. It will appear pink in basic solutions and clear in acidic solutions. ... It is known as the titrant.
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3 years ago
Which has a greater volume, 10 grams of water or 10 grams of acetone?
WINSTONCH [101]

Density is defined as the ratio of mass to the volume.

Density = \frac{Mass}{Volume}          (1)

Mass of water = 10 grams

Mass of acetone  = 10 grams

Density of water  = 1 \frac{g}{cm^{3}}

Density of acetone  = 0.7857 \frac{g}{cm^{3}}

Put the value of density of water and its mass in equation (1)

1 \frac{g}{cm^{3}} =  \frac{10 g}{volume}

Volume of water =  10 cm^{3}

Put the value of density of acetone and its mass in equation (1)

0.7857 \frac{g}{cm^{3}} =  \frac{10 g}{volume}

Volume of acetone = 12.72 cm^{3}

Thus, volume of acetone is more than volume of water because the density of acetone is lower.

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The volume increases when the balloon temperature increases.

<u>Explanation:</u>

-10 F is converted into Kelvin as 249 K.

0°C is nothing but 0+ 273 = 273 K

And the room temperature is 25°C which is converted into Kelvin as 273 + 25 = 298 K.

249 K is below room temperature.

As per the Charles' law volume and temperature are directly proportional to each other, when the pressure of the gas remains constant.

V ∝ T

As the balloon temperature increases, the volume also increases.

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Answer: There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{63.00g}{18g/mol}=3.5moles

1 mole of H_2O contains =  6.023\times 10^{23} molecules

Thus 3.5 moles of H_2O contains =  \frac{6.023\times 10^{23}}{1}\times 3.5=21.08\times 10^{23} molecules.

There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

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