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Andrews [41]
3 years ago
9

A printed circuit board (PCB) is supported by a chassis that is attached to a vibrating motor. The board is 1.6 mm thick, 200 mm

wide, 254 mm long, and has a mass of 0.6 kg. Neglect damping, model the board as a doubly clamped beam, determine its stiffness and natural frequency, and compute the displacement transmissibility if the chassis vibrates at 60 Hz due to motor unbalance. The board is made from e poxy fiberglass for which E = 1.38 x 10^10 N/m2
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

jtejyrkekdkeludmydmumud

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Both Newton's Law of Universal Gravitation and Coulomb's Law follow the ...
Romashka [77]

Answer:

inverse square relationship

Explanation:

Both the Newton's law of universal gravitation and coulomb's law have their force inversely proportion to the square of the distance between the bodies.

8 0
2 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.83 times a second. A tack is stuck in the tire a
timama [110]

Answer:

The tangential speed of the tack is 6.988 meters per second.

Explanation:

The tangential speed experimented by the tack (v), measured in meters per second, is equal to the product of the angular speed of the wheel (\omega), measured in radians per second, and the distance of the tack respect to the rotation axis (R), measured in meters, length that coincides with the radius of the tire. First, we convert the angular speed of the wheel from revolutions per second to radians per second:

\omega = 2.83\,\frac{rev}{s} \times \frac{2\pi\,rad}{1\,rev}

\omega \approx 17.781\,\frac{rad}{s}

Then, the tangential speed of the tack is: (\omega \approx 17.781\,\frac{rad}{s}, R = 0.393\,m)

v = \left(17.781\,\frac{rad}{s} \right)\cdot (0.393\,m)

v = 6.988\,\frac{m}{s}

The tangential speed of the tack is 6.988 meters per second.

7 0
3 years ago
Assume the ground is uniformly level. If the horizontal component a projectile's velocity is doubled, but the vertical component
Katarina [22]

Answer:

Explanation:

Time of flight = 2 x u sinα / g where u sinα is vertical component of projectile's velocity u .

So Time of flight = 2 x vertical component / g

vertical component = constant

g is also constant so

Time of flight will also be constant .

It will remain unchanged .

3 0
3 years ago
A certain lightbulb has a tungsten filament with a resistance of 26 Ω when cold and 170 Ω when hot. If the equation R = R0 [1 +
iris [78.8K]

Answer:

Explanation: The equation that relates resistance of tungsten at different temperatures is as follows

R = R₀ [1 + α ∆T]  , R₀ is resistance at lower temperature , R is resistance at higher temperature . α is temperature coefficient of resistivity and ∆T is rise in temperature .

Putting the values

170 = 26 [1 + .0045 ∆T]

∆T = 1230.75

lower temperature = 40◦C

higher temperature = 1230 + 40

= 1270◦C

5 0
3 years ago
An object in space is initially stationary relative to the Earth. Then, a force begins acting on the object, starting with a for
11111nata11111 [884]

Answer:

v_f =63 m/s

Explanation:

given,

starting force = 0 N

uniform rate increase to 36 N

time of action of Force = 35 s

mass of the body = 10 Kg

Speed of the object = ?

From the given data

if we plot F-t curve  we will get a triangular shape

we know,

Impulse = Area between F-t curve

            = (1/2) x base x height

             = 0.5 x 35 x 36

             = 630 N.s

now use Impulse-momentum theorem

Impulse = change in momentum

630 = 10 x (v_f - vi)

630 = 10 x (v_f - 0)

v_f =63 m/s

Speed of the object at 35 sec is equal to v_f =63 m/s

8 0
3 years ago
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