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Anna [14]
3 years ago
7

Which action has more power

Physics
2 answers:
Sergio039 [100]3 years ago
3 0
What action over what
V125BC [204]3 years ago
3 0
Which action is it? There is no picture
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The picture shows an object resting on a balance.
Maslowich

Answer:

4.90kgm^-2

Explanation:

4 0
2 years ago
We use a battery to cause a continuous potential difference by getting charges to separate. Explain why the terminals of a batte
QveST [7]

Answer:

To create an electric potential difference between the ends of the conductor.

Explanation:

For current to flow, there must exist an electric potential difference between the ends of the conductor. This PD is provided by the electromotive force stored within the battery. Unless there is a connection between the terminals no PD will exist between the terminals.

6 0
3 years ago
Which of the following is an electromagnetic wave characteristic which is similar to a particle
Alenkinab [10]

Answer: Photoelectric wave

Explanation: Because it represents an interaction between light and matter that describes light as an electromagnetic wave.

6 0
3 years ago
A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

    (m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

                 k = [(m)×(v^2)]/(x^2)

                 k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

                 k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

             v^2 = [(k)(x^2)]/m

                 v =  \sqrt{ [(k)(x^2)]/m}

                 v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

                    = 0.491 m/s

8 0
3 years ago
Read 2 more answers
What is the potential energy of a 2500 g object suspended 5 m above the earth's surface?
alexandr402 [8]

Answer:

Explanation:

Potential energy, which is the energy a body assumes at a position, can be calculated using the formula:

P.E = m × g × h

Where;

m = mass (kg)

g = acceleration due to gravity (10m/s²)

h = height (m)

7 0
3 years ago
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