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stich3 [128]
4 years ago
8

What ratio is equal to 30/75?

Mathematics
1 answer:
Diano4ka-milaya [45]4 years ago
8 0
It would be: 30/75 = 6/15 = 2/5

So, it's reduced & most simple form is 2/5

Hope this helps!
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Maude's living room is in the shape of a rectangle. Its dimensions are 21 feet by 14 feet. Find the length of the diagonal of th
DaniilM [7]
Use the pythagorean theorem A²+B²=C²

Use 21ft for A 
Use 14ft for B 
Then solve for C (the diagonal)

21²+14²=C²

441+196=C²

673=C²

√<u />673 = √C²

C≈25.24 or if you leave in radical form it is the square root of 637
5 0
4 years ago
In order to purchase a new backyard patio in 3 years, the Robinsons have decided to deposit $1,700 in an account that earns 6% p
tankabanditka [31]

Answer: A = 2,034.356 ≈ $2,034.36

$2,034.36 will be in the account in 3 years

Step-by-step explanation:

Given that ;

P = $1,700

Rate r = 6%

Time period (t) = 3 years

now to find how much money will be in the account in 3 years

we say;

A = P ( 1 + r/n )^nt

A = 1,700 ( 1 + 0.06/12) ¹²ˣ³

A = 1,700 ( 1.19668)

A = 2,034.356 ≈ $2,034.36  

3 0
3 years ago
f(x) = (x -2) +4 Given: g(x) = (x - 5)2 + 4 When compared to the graph of f(x), the graph of g(x) is (1) shifted 3 units to the
Verizon [17]

Answer:

Option 2 is correct

Step-by-step explanation:

The graphs

6 0
3 years ago
Please helpp me do this...
emmainna [20.7K]

I think your just showing of your nails but the awnser 69 lol

3 0
3 years ago
Please help if you know how to do this, thanks
adelina 88 [10]

9514 1404 393

Answer:

  4) y = -3(x+2)^2 +4; y = -3x^2-12x-8; ABC=(-3, -12, -8)

  5) y = 0.5(x-1)^2-2; y = 0.5x^2-x-1.5; (h,k) = (1, -2)

  6) y = -0.3(x+2)^2-6; y = -0.3x^2-1.2x-7.2; (h,k) = (-2, -6)

Step-by-step explanation:

Writing a quadratic equation through a set of points is most easily done using the regression function of a graphing calculator or spreadsheet.

4) see the first attachment

  y = -3(x+2)^2 +4 . . . vertex form

  y = -3x^2 -12x -8 . . . standard form (A, B, C) = (-3, -12, -8)

__

5) see the second attachment

  y = 0.5(x -1)^2 -2 . . . vertex form; vertex = (1, -2)

  y = 0.5x^2 -x -1.5 . . . standard form

__

6) see the third attachment

  y = -0.3(x +2)^2 -6 . . . vertex form; vertex = (-2, -6)

  y = -0.3x^2 -1.2x -7.2 . . . standard form

_____

Doing this without machine help requires you pick a form of the equation you want, fill in the x- and y-values for three of the given points, then solve the resulting equations for the unknown parameters. Usually, we use the form ...

  y = ax^2 +bx +c

which will result in three linear equations for a, b, c. Those can be solved by any of the usual methods.

6 0
4 years ago
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