The present carbon skeleton in an ether is C-C-C-O-C-C-C because ethers conatins C-O-C as functional group
Answer:
1.64 moles O₂
Explanation:
Part A:
Remember 1 mole of particles = 6.02 x 10²³ particles
So, the question becomes, how many '6.02 x 10²³'s are there in 9.88 x 10²³ molecules of O₂?
This implies a division of given number of particles by 6.02 x 10²³ particles/mole.
∴moles O₂ = 9.88 x 10²³ molecules O₂ / 6.02 x 10²³ molecules O₂ · mole⁻¹ = 1.64 mole O₂
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Part B needs an equation (usually a combustion of a hydrocarbon).
Answer:
B if they run out of fuel then they would probably keep going because there is nothing that would stop them other than like a planet or something.
Explanation:
Question:
How many neutrons are there in 186W
Answer:
112
hope it helps (^^)
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