Answer:
The percentage mixture of 2-methyl-1-butene would be in between the 45% and 70%.
Explanation:
Potassium prop oxide is the intermediate base as compared to the potassium hydroxide which is less bulky strong base and potassium tert-butoxide which is bulky base. Bulky base can minimize the substitution reaction by causing hinders the approach of carbon attack and KOH is the strong base which less effective in minimizing the substitution reaction.
You just need to multiply the terms and transform to kj by dividing by 1000
1) 10.4kj
2) 14.5 kj
3) 44.8 kj
4) 1.04 kj
and there you go.
It’s been awhile but I think it is c
THE CORRDCT ANSWER IS TRUE
