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Alex Ar [27]
2 years ago
5

Determine the number of atoms of O in 60.1 moles of Fe₂(SO₃)₃.

Chemistry
1 answer:
kvasek [131]2 years ago
4 0

Answer:

3.310308*10^26

Explanation:

nO=9nFe2(SO3)3=9*60.1=540.9 moles

number of atoms: 540.9*6.02*10^23

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<span>Concentration of [OH]</span>⁻<span> in solution:
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