Answer:
285 g of P₄
Explanation:
Let's consider the following balanced equation.
2 Ca₃(PO₄)₂ + 6 SiO₂ + 10 C → 6 CaSiO₃ + P₄ + 10 CO
We know the following relations:
- 100 g of phosphorite contain 75 g of Ca₃(PO₄)₂
- 2 moles of Ca₃(PO₄)₂ produce 1 mole of P₄
- The molar mass of Ca₃(PO₄)₂ is 310 g/mol
- The molar mass of P₄ is 124 g/mol
Then, for 1.9 kg of phosphorite:
Answer: The temperature of the gas is 132.25K and -140.75°C
Explanation:
Given that:
Volume of helium gas (V) = 18.5L
Temperature of helium gas (T) = ?
Pressure (P) = 0.85 atm
Number of moles (n) = 1.45 moles
Molar gas constant (R) is a constant with a value of 0.082 atm L K-1 mol-1
Then, apply the formula for ideal gas equation
pV = nRT
0.85atm x 18.5L = 1.45 moles x 0.082 atm L K-1 mol-1 x T
15.725 atm•L = 0.1189 atm•L•K-1 x T
T = 15.725 atm•L / 0.1189 atm•L•K-1
T = 132.25K
Given that temperature in Kelvin is 132.25, convert it to Celsius by subtracting 273
So, T(in Celsius) = 132.25K - 273
= -140.75°C
Thus, the temperature of the gas is 132.25K and -140.75°C
To find the mass of glucose, you must multiply the atomic weight of each of the elements in the molecule by the subscripts in the formula:
Then you add all of them together:
Therefore, the molar weight of glucose is 180.15 grams.
<h3><u>Answer;</u></h3>
+2
<h3><u>Explanation</u>;</h3>
- The electron configuration ofthe atom is 1s2 2s2 2p6 3s2. Upon forming an ion, its new configuration is 1s2 2s2 2p6.
- The atom has lost two electrons to form an ion which is positively charged with a charge of +2.
- In the given electronic configuration of an atom, '3s' shell is the outermost shell in which two electrons are present. For the stable configuration, these two electrons will be lost easily from the outer shell and atom will carry (+2).
- The atom has 12 electrons, and looses 2 electrons to attain stable configuration forming a positively charged ion with 10 electrons.
Answer:
D. 2:5
Explanation:
It has 5 valency electrons
