The answer you are looking four is 4/2 or 4CO2/2C2H6
Answer:
The value is 
Explanation:
From the question
The equation given is
NiO(s) + H2(g) ⇌ Ni(s) + H2O(g) Kc=40 (1)
NiO(s) +CO(g) ⇌ Ni(s) +CO2(g) Kc=600 (2)
Generally the reverse of the second equation as shown below
Ni(s) +CO2(g) ⇌ NiO(s) + CO(g) (3)
The equilibrium constant becomes
Now adding 1 and 3 we obtain
NiO(s) + H2(g)+ Ni(s) +CO2(g) ⇌ Ni(s) + H2O(g)+NiO(s) + CO(g)
CO2(g) + H2(g) ⇌ CO(g) + H2O(g)
Hence the equilibrium constant for the resulting equation is mathematically evaluated as

=> 
=> 
Answer:
7.32g of HNO3 are required.
Explanation:
1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.
From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.
2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:
• starting with the 4.30 grams of Ca(OH)2.
,
• using the molar mass of Ca(OH)2 (74g/mol).
,
• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .
,
• using the molar mass of HNO3 (63.02g/mol).

So, 7.32g of HNO3 are required.
Answer:
neutrons should be added with the protons