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FinnZ [79.3K]
4 years ago
5

A block rests on a frictionless table on Earth. After a 20-N horizontal force is applied to the block, it accelerates at 3.9 m/s

2. Then the block and table are carried to the moon, where the acceleration due to gravity is 1.62 m/s2. A horizontal force of 10 N is then applied to the block. What is the acceleration?
Physics
2 answers:
Airida [17]4 years ago
7 0
I think it's 1.95m/s^2
svp [43]4 years ago
4 0

Answer:

1.95m/s^2

Explanation:

We should understand that acceleration due to gravity does not affect the horizontal acceleration of the block, whether on earth or on the moon. On earth we use the following relationship to obtain the mass of the object.

f=ma\\f=20N\\a=1.62m/s^2\\m=f/a\\m=20/1.62\\m=5.128kg

The mass does not change whether on earth or on the moon. Mass is the quantity of matter contained in a body and it does not change with the location of the body. The same relationship between force, mass and acceleration also holds over there.

Therefore, on the moon;

f=10N\\a=?\\m=5.128kg\\a=f/m\\a=10/5.128\\a=1.95m/s^2

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As per the question the volume of mercury  is given as 0.002 m^3 at 20 degree Celsius.

We are asked to calculate the volume of the mercury at 50 degree Celsius.

This problem is based on thermal expansion of matter.

Let us consider the initial and final volume of the mercury is denoted as -

                                  v_{1} \ and\ v_{2}

Let the initial and final temperature of the mercury is denoted as -

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The change in temperature is

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The coefficient of of volume expansion of mercury [ \gamma ] at 20 degree Celsius is 0.00018 per centigrade.

As per volume expansion of liquid,

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Hence volume at 50 degree Celsius is calculated as-

                               v_{2} =v_{1} [1+\gamma[50-30]]

                                       = 0.002[1+0.00018*30]

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As per the options given in the question ,option A is close to the calculated value. So option A is right.


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