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aalyn [17]
4 years ago
8

A ball is dropped from the roof of a building. the mass of the ball is 3.0 kg. what is the potential energy of the ball in the i

nstant that it is exactly 18.0 meters above the ground?
Physics
1 answer:
vitfil [10]4 years ago
6 0
According to given condition there is no height(m) given from roof of building to the ground, there height given 18 m at a point above the ground.                         So, h=18m  ,                mass=3kg     ,         g=9.8m/s2                                                                      P.E=mgh                                                                                                                P.E=(3)(9.8)(18)                                                                                                      P.E=529J
                                      
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What is the identity of a sample that has a volume of 92.5 cm3 and a mass of 249.8 g?
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Here, mass = 249.8 g
volume = 92.5 cm³

Substitute their values, 
d = 249.8 / 92.5
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In short, Your Answer would be "Aluminum" 

Hope this helps!
3 0
3 years ago
Read 2 more answers
A girl rides her bike at 2.52 m/s on the way to her friends how which is 628 m away.
Harrizon [31]

Answer: 249 seconds

Explanation:

Speed of bike = 2.52 m/s

Distance = 628 m

Time taken = ? ( let the unknown value be Z)

Recall that speed is the distance covered per unit time.

Hence, speed = Distance / Time taken

Time taken = Distance / speed

Z = 628m / 2.52 m/s

Z = 249.2 seconds (Round to nearest tenth i.e 249 seconds)

Thus, it takes 249 seconds for the girl to get to her friends house

7 0
3 years ago
PLEASE HELP what is the velocity of an airplane that travels 1,200 km in 2.2 hours​
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3 years ago
julia throws a ball vertically upward from the ground with a speed of 5.89m/s. Andrew catches it when it is on its way down at a
aliya0001 [1]
Vo = 5.89 m/s Y = 1.27 m g = 9.81 m/s^2 
Time to height 
Tr = Vo / g Tr = (5.89 m/s) / (9.81 m/s^2) Tr = 0.60 s 
Max height achieved is:
H = Vo^2 / [2g] H = (5.89 )^2 / [ 2 * (9.81) ] H = (34.69) / [19.62] H = 1.77 m 
It falls that distance, minus Andrew's catch distance:
h = H - Y h = (1.77 m) - (1.27 m) h = 0.5 m 
Time to descend is therefore:
Tf = √ { [2h] / g ] Tf = √ { [ 2 * (0.5 m) ] / (9.81 m/s^2) } Tf = √ { [ 1.0 m ] / (9.81 m/s^2) } Tf = √ { 0.102 s^2 } Tf = 0.32 s 
Total time is rise plus fall therefore:
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8 0
3 years ago
In a golf ball game, a person hits the golf ball with a club. The club is in contact with the ball, which is initially at rest,
Anon25 [30]

Answer:

F=4040.81 N

Explanation:

Given that

Time ,t= 2.45 ms

Mass ,m= 0.055 kg

v= 1.8 x 10² m/s = 180 m/s

We know that rate of change in the linear momentum is known as force.

Momentum P = m v

F=\dfrac{dP}{dt}

Therefore force F

F=\dfrac{\Delta P}{\Delta t}

F=\dfrac{0.055\times 180}{2.45\times 10^{-3}}\ N

F=4040.81 N

Therefore force on the ball will be 4040.81 N

6 0
3 years ago
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