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Ghella [55]
3 years ago
6

Three observers watch a train pull away from a station toward the right of the platform. Observer A is in one of the train’s car

s; Observer B is on the station platform; and Observer C is on another train traveling in the opposite direction along a parallel track. How would the observer in each frame of reference describe the motion of the train? According to Newton’s laws of motion, how would the motion in the station platform’s frame of reference change if the conductor applied the brakes to the train? Does universal gravitation affect the train? Explain why or why not.
Physics
1 answer:
juin [17]3 years ago
5 0

Observer A is moving inside the train

so here observer A will not be able to see the change in position of train as he is standing in the same reference frame

So here as per observer A the train will remain at rest and its not moving at all

Observer B is standing on the platform so here it is a stationary reference frame which is outside the moving body

So here observer B will see the actual motion of train which is moving in forward direction away from the platform

Observer C is inside other train which is moving in opposite direction on parallel track. So as per observer C the train is coming nearer to him at faster speed then the actual speed because they are moving in opposite direction

So the distance between them will decrease at faster rate

Now as per Newton's II law

F = ma

Now if train apply the brakes the net force on it will be opposite to its motion

So we can say

- F = ma

a = \frac{-F}{m}

so here acceleration negative will show that train will get slower and its distance with respect to us is now increasing with less rate

It is not affected by the gravity  because the gravity will cause the weight of train and this weight is always counterbalanced by normal force on the train

So there is no effect on train motion



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ki77a [65]

Answer:

Acceleration of that planet is 30 \frac{m}{s^{2} }.

Given:

initial speed of hammer = 0 \frac{m}{s}

time = 1 s

distance = 15 m

To find:

Acceleration due to gravity = ?

Formula used:

Distance covered by hammer is given by,

s = ut + \frac{1}{2} a t^{2}

s = distance

u = initial speed of hammer

t = time taken by hammer to reach ground

a = acceleration

Solution:

Distance covered by hammer is given by,

s = ut + \frac{1}{2} a t^{2}

s = distance

u = initial speed of hammer

t = time taken by hammer to reach ground

a = acceleration

u = 0

t = 1 s

s = 15 m

a = g

Thus substituting these value in above equation.

15 = 0 + \frac{1}{2} g 1^{2}

g = 15 × 2

g = 30 \frac{m}{s^{2} }

Thus, acceleration of that planet is 30 \frac{m}{s^{2} }.

8 0
3 years ago
Where coastal rock is softer, waves erode the land faster ​
prohojiy [21]

Answer:

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5 0
2 years ago
if a car that is 100 feet in front of you on route 70 west slams on the brakes while you are traveling 65 miles per hour (95 fee
fenix001 [56]

Answer:

t = 1.05 s

Explanation:

Given,

The distance between your vehicle and car, 100 ft

The constant speed of your vehicle, u = 95 ft/s

Since, the velocity is constant, a =0

If the car stopped suddenly, time left for you to hit the brake, t = ?

Using the second equation of motion,

                           S = ut + ½ at²

Substituting the given values in the equation

                           100 = 95 x t

                             t = 100/95

                               = 1.05 s

Hence, the time left for you to hit the brakes and stop before rear ending them, t = 1.05 s

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suter [353]

Answer:

B. Acidic

Explanation:

Neutral an Basic solutions wouldn't create any reaction

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2 years ago
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harkovskaia [24]

Answer:

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