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maxonik [38]
3 years ago
7

If the moon were twice as far from years as it is now the following would be true

Physics
1 answer:
zubka84 [21]3 years ago
7 0
The question is incomplete.

The distance between the Moon and Earth influences: 1) the attractive gravitational force between them, 2) the tides, 3) the eclipses, 4) the period of each full turn of the moon around the Earth.

Assuming the question refers to the gravitational attraction, we must use the fact that, as per, Newton's Universal Gravitaional Law, the attractive force between the two bodies is inversely related to the square distance that separates them.

Then, if the Moon were twice as far, the gravitational pull would be one fourth (1/4) of actual pull.

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Gravitational force is given as

F = \frac{Gm_1m_2}{r^2}

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Now here since the tool is at finite distance from Astronaut and Moon, Sun, Earth

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The Astronaut

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A variable-length air column is placed just below a vibrating wire that is fixed at both ends. The length of the air column, ope
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Answer:

The speed of transverse waves in the wire is 234.26 m/s.

Explanation:

Given that,

Length of wire = 129 cm

Speed of sound in air = 340 m/s

First position of resonance = 31.2 cm

We need to calculate the wavelength

For pipe open at one end and closed at other, there is node at closed end and an anti node at open end for 1st resonance.

At 1st resonance,

L=\dfrac{\lambda}{4}

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Put the value into the formula

\lambda=4\times31.2\times10^{-2}

\lambda=1.248\ m

We need to calculate the frequency of sound in pipe

Using formula of frequency

f=\dfrac{v}{\lambda}

Put the value into the formula

f=\dfrac{340}{1.248}

f=272.4\ Hz

We need to calculate the node distance

For the wire, there are 3 segments, so 4 nodes

Node-node distance ,

L=\dfrac{l}{3}

L = \dfrac{129}{3}

L=43\ cm

We need to calculate the wavelength of the wire

Using formula of length

L=\dfrac{\lambda}{2}

\lambda=L\times 2

Put the value into the formula

\lambda=43\times2

\lambda=86\ cm

We need to calculate the speed of the wave

Using formula of frequency

f=\dfrac{v}{\lambda}

v=f\times\lambda

Put the value into the formula

v=272.4\times86\times10^{-2}

v=234.26\ m/s

Hence, The speed of transverse waves in the wire is 234.26 m/s.

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