I need help attacking this problem A steel ball is dropped onto a hard floor from a height of 1.95 m and rebounds to a height of
1 answer:
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Answer:
q = 2.65 10⁻⁶ C
Explanation:
For this exercise we use Coulomb's law
F =
In this case they indicate that the load is of equal magnitude
q₁ = q₂ = q
the force is attractive because the signs of the charges are opposite
F =
q =
we calculate
q =
q = Ra 7 10-12
q = 2.65 10⁻⁶ C
Answer:
- The work made by the gas is 7475.69 joules
- The heat absorbed is 7475.69 joules
Explanation:
<h3>Work</h3>We know that the differential work made by the gas its defined as:
We can solve this by integration:
but, first, we need to find the dependence of Pressure with Volume. For this, we can use the ideal gas law
This give us
As n, R and T are constants
But the volume is:
Now, lets use the value from the problem.
The temperature its:
The ideal gas constant:
So:
We know that, for an ideal gas, the energy is:
where its the internal energy of the gas. As the temperature its constant, we know that the gas must have the energy is constant.
By the first law of thermodynamics, we know
where is the Work made by the gas (please, be careful with this sign convention, its not always the same.)
So: