Answer:
Approximately (assuming that .)
Explanation:
Let denote the force that this spring exerts on the object. Let denote the displacement of this spring from the equilibrium position.
By Hooke's Law, the spring constant of this spring would ensure that .
Note that the mass of the object attached to this spring is . Thus, the weight of this object would be .
Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, .
The spring in this question was stretched downward from its equilibrium by:
.
(Note that is negative since this displacement points downwards.)
Rearrange Hooke's Law to find in terms of and :
.
Answer:
7.45
Explanation:
At 3.0 m PE = m*g*3.0, KE = m*g*(4.0 - 3.0)
At 2.0 m PE = m*g*2.0, KE = m*g*(4.0 - 2.0)
At 3.0 m PE = m*g*1.0, KE = m*g*(4.0 - 1.0)
At 0 m PE = 0, KE = m*g*h = total energy = 7.45 J
Answer:
So an MA of 1 then 2 newtons would be required to lift 20 KG
F = Mass Acceleration = 20 x 10 = 200 Newtons so to lift the same mass with 50 newtons then the mechanical advantage hast to be 200 divided by 50 = 4
Answer:
hello there the answer is swims
Explanation:
it would really not make sense " the women in the pool swim"
"the women in the pool swims"
hope this helped!