What are some examples of pressure

Julli [10]

The answer is the first one

6 0

3 years ago

The design speed of a multilane highway is 60 mi/hr. What is the minimum stopping sight distance that should be provided on the

kicyunya [14]

Answer:

Part a: When the road is level, the minimum stopping sight distance is 563.36 ft.

Part b: When the road has a maximum grade of 4%, the minimum stopping sight distance is 528.19 ft.

Explanation:

Part a

When Road is Level

The stopping sight distance is given as

$SSD=1.47 ut +\frac{u^2}{30 (\frac{a}{g} \pm G)}$

Here

SSD is the stopping sight distance which is to be calculated.
u is the speed which is given as 60 mi/hr
t is the perception-reaction time given as 2.5 sec.
a/g is the ratio of deceleration of the body w.r.t gravitational acceleration, it is estimated as 0.35.
G is the grade of the road, which is this case is 0 as the road is level

Substituting values

$SSD=1.47 ut +\frac{u^2}{30 (\frac{a}{g} \pm G)}\\SSD=1.47 \times 60 \times 2.5 +\frac{60^2}{30 \times (0.35-0)}\\SSD=220.5 +342.86 ft\\SSD=563.36 ft$

So the minimum stopping sight distance is 563.36 ft.

Part b

When Road has a maximum grade of 4%

The stopping sight distance is given as

$SSD=1.47 ut +\frac{u^2}{30 (\frac{a}{g} \pm G)}$

Here

SSD is the stopping sight distance which is to be calculated.
u is the speed which is given as 60 mi/hr
t is the perception-reaction time given as 2.5 sec.
a/g is the ratio of deceleration of the body w.r.t gravitational acceleration, it is estimated as 0.35.
G is the grade of the road, which is given as 4% now this can be either downgrade or upgrade

For upgrade of 4%, Substituting values

$SSD=1.47 ut +\frac{u^2}{30 (\frac{a}{g} \pm G)}\\SSD=1.47 \times 60 \times 2.5 +\frac{60^2}{30 \times (0.35+0.04)}\\SSD=220.5 +307.69 ft\\SSD=528.19 ft$

So the minimum stopping sight distance for a road with 4% upgrade is 528.19 ft.

For downgrade of 4%, Substituting values

$SSD=1.47 ut +\frac{u^2}{30 (\frac{a}{g} \pm G)}\\SSD=1.47 \times 60 \times 2.5 +\frac{60^2}{30 \times (0.35-0.04)}\\SSD=220.5 +387.09 ft\\SSD=607.59ft$

So the minimum stopping sight distance for a road with 4% downgrade is 607.59 ft.

As the minimum distance is required for the 4% grade road, so the solution is 528.19 ft.

3 0

3 years ago

A disc of mass m slides with negligible friction along a flat surface with a velocity v. The disc strikes a wall head-on and bou

qwelly [4]

Answer:

-v/2

Explanation:

Given that:

a disc of mass m

Collides with the wall going through a sliding motion on on the plane smooth surface.

Upon rebounding from the wall its kinetic energy becomes one-fourth of the initial kinetic energy before collision.

We know, kinetic energy is given as:

$KE_i=\frac{1}{2}. m.v^2$

consider this to be the initial kinetic energy of the body.

Now after collision:

$KE_f=\frac{1}{4}\times KE_i$

$KE_f=\frac{1}{4} \times \frac{1}{2}\times m.v^2$

Considering that the mass of the body remains constant before and after collision.

$KE_f=\frac{1}{2}\times m.(\frac{v}{2})^2$

Therefore the velocity of the body after collision will become half of the initial velocity but its direction is also reversed which can be denoted by a negative sign.

3 0

2 years ago

You are playing a game of soccer. Describe as many actionreaction pairs in this situation as you can think of.

marissa [1.9K]

Slide tackle, goalkeeping, avoiding getting tackled, controlling the ball in the air, shooting from a hard angle etc

3 0

2 years ago

Orbitals that are of equal energy may be referred to as.

ivanzaharov [21]

Answer:

degenerate

Explanation:

5 0

2 years ago