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mixer [17]
3 years ago
5

A cheetah can run at approximately 100 km/hr and a gazelle at 80.0 km/hr. If both animals are running at fullspeed, with the gaz

elle 70.0 m ahead, how long before the che
Physics
1 answer:
brilliants [131]3 years ago
6 0

Answer:

12.6 seconds

Explanation:

With respect to the gazelle, the cheetah has a relative speed of 100 - 80 = 20 km/hr.

We convert from km/hr to m/s.

\dfrac{20000\text{ m}}{3600\text{ s}} = \dfrac{50}{9}\text{ m/s}

At this relative speed, the cheetah will overtake the gazelle in time <em>t</em> given by

v= \dfrac{d}{t}

<em>d</em> is the distance and <em>v</em> is the relative speed.

t = \dfrac{d}{v} = \dfrac{70.0}{50/9} = 12.6\text{ s}

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5 points
Drupady [299]

Answer:

distance is not a vector. it is scalar

5 0
3 years ago
An 80-kg football player travels to the right at 8 m/s and a 120-kg player on the opposite team travels to the left at 4.0 m/s.
77julia77 [94]

Answer:

See Explanation

Explanation:

m1(v1) + m2(v2)

Opposite turns the plus to subtraction.

80(8) - 120(4.0)

60 - 480 = 160 kg m/s to the right

7 0
2 years ago
How can I solve this?
inysia [295]
There is no equation here
3 0
3 years ago
Yasmin determines the velocity of a car to be 15m/s. The accepted value for the velocity of the car is 15.6m/s. What is yasmins
zaharov [31]

Percent error is calculated as follows:

% = ( |15-15.6| / 15.6 ) *  100%

% = (0.6/15.6) * 100%

% = 0.0385 * 100%

% = 3.85%

Hope this helped!

7 0
4 years ago
Read 2 more answers
A 5 kg block is sliding down a plane inclined at 30^0 with a constant velocity of 4 m/s. To determine the coefficient of frictio
Leya [2.2K]

Answer:

The necessary information is if the forces acting on the block are in equilibrium

The coefficient of friction is 0.577

Explanation:

Where the forces acting on the object are in equilibrium, we have;

At constant velocity, the net force acting on the particle = 0

However, the frictional force is then given as

F = mg sinθ

Where:

m = Mass of the block

g = Acceleration due to gravity and

θ = Angle of inclination of the slope

F = 5×9.81×sin 30 = 24.525 N

Therefore, the coefficient of friction is given as

24.525 N = μ×m×g × cos θ = μ × 5 × 9.81 × cos 30 = μ × 42.479

μ × 42.479 N= 24.525 N

∴ μ = 24.525 N ÷ 42.479 N = 0.577

3 0
3 years ago
Read 2 more answers
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