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777dan777 [17]
2 years ago
13

If a certain mass of mercury has a volume of 0.002m3 at a temperature of 20°C, what will be the volume at 50°C,

Physics
1 answer:
USPshnik [31]2 years ago
3 0

Set this up as a proportion.

.002 m^3/20 degrees = x/50 degrees

solve for x

x = .005 m^3

If you found this helpful, please brainliest me!

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Crank

Answer:

Hi...

14-20=-6...displacement

14+20=34...distance

3 0
2 years ago
The deepest point in the ocean is 11 km below sea level, deeper than Mt. Everest is tall.
34kurt

The pressure at the depth 11 km below sea level can be calculated using

P=ρgh

P is pressure, ρ is the density of the fluid; g is the gravitational constant, h is the height from the surface, or depth that the object is submerged.

P = ( 1000 kg/ m3) ( 9.81 m.s2)( 11 000m) + 1 atm

P = 107,910,000 pa ( 1 atm/ 101 325 Pa) + 1 atm = 1066 atm

8 0
3 years ago
An object has a kinetic energy ke, and potential energy pe. it also has a rest energy e0. what is the object's total energy e?
Dmitriy789 [7]
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7 0
3 years ago
Consider an ideal gas at 27.0 degrees Celsius and 1.00 atmosphere pressure. Imagine the molecules to be uniformly spaced, with e
My name is Ann [436]

To solve the exercise it is necessary to keep in mind the concepts about the ideal gas equation and the volume in the cube.

However, for this case the Boyle equation will not be used, but the one that corresponds to the Boltzmann equation for ideal gas, in this way it is understood that

PV =NkT

Where,

N = Number of molecules

k = Boltzmann constant

V = Volume

T = Temperature

P = Pressure

Our values are given as,

N = 1

k = 1.38*10^{-23}J/K

T = 27\°C = 27\°C + 273 = 300K

P = 1atm = 101325Pa

Rearrange the equation to find V we have,

V = \frac{NkT}{P}

V = \frac{1(1.38*10^{-23})(300K)}{101325Pa}

V = 4.0858*10^{-26}m^3

We know that length of a cube is given by

V = L^3

Therefore the Length would be given as,

L = V^{1/3}

L = (4.0858*10^{-26})^{1/3}

L = 3.445*10^{-9}m

Therefore each length of the cube is 3.44nm

7 0
3 years ago
How much power is required to lift a 60 kg bed to the top of a 3 meter flight of stairs in 10 seconds?
Zigmanuir [339]

Answer:

176.58Watts

Explanation:

Power= work done /time

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Power=mgh/t

Power= (60kg) * (9.81m/s^2) * (3m)/10s

Power= 176.58Watts

8 0
3 years ago
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