Answer:
It would be D.
Step-by-step explanation:
Hope this helps!!!
Answer:
y=6x-8 is the answer
Step-by-step explanation:
the formula is y=mx+b. m is the slope and b is the y intercept.
Answer:
a
Step-by-step explanation:
<h2>
Answer:</h2>
For a real number a, a + 0 = a. TRUE
For a real number a, a + (-a) = 1. FALSE
For a real numbers a and b, | a - b | = | b - a |. TRUE
For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c). FALSE
For rational numbers a and b when b ≠ 0, is always a rational number. TRUE
<h2>Explanation:</h2>
- <u>For a real number a, a + 0 = a. </u><u>TRUE</u>
This comes from the identity property for addition that tells us that<em> zero added to any number is the number itself. </em>So the number in this case is
, so it is true that:

- For a real number a, a + (-a) = 1. FALSE
This is false, because:

For any number
there exists a number
such that 
- For a real numbers a and b, | a - b | = | b - a |. TRUE
This is a property of absolute value. The absolute value means remove the negative for the number, so it is true that:

- For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c). FALSE
This is false. By using distributive property we get that:

- For rational numbers a and b when b ≠ 0, is always a rational number. TRUE
A rational number is a number made by two integers and written in the form:
Given that
are rational, then the result of dividing them is also a rational number.
Answer:
![\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given [Missing from the question]
![\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Required

This implies that, we form a new matrix where the second row of the new matrix is a product of -3 and the second row of the previous matrix.
So, we have:
![Initial =\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=Initial%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3*1&-3*3&-3*-1&|-3*-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%2A1%26-3%2A3%26-3%2A-1%26%7C-3%2A-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)