The flowerpot is in free fall, so it moves by uniformly accelerated motion with acceleration equal to
. Its initial speed is zero, so we can write the law of motion for the pot as
where S(t) is the distance covered by the pot after a time t.
We want to find the time t at which the pot reaches ground, so the time t after which the pot has covered 9.2 m, therefore we should require S(t)=9.2 m and find t:
Answer:
D remove 1.5 ML of liquid.
Explanation:
Answer:
Explanation:
Actual weight, Wo = 5 N
Apparent weight, W = 4.5 N
density of water = 1 g/cm^3 = 1000 kg/m^3
density of gold, = 19.32 g/cm^3 = 19.32 x 1000 kg/m^3
Buoyant force = Actual weight - Apparent weight
Volume x density of water x g = 5 - 4.5
V x 1000 x 9.8 = 0.5
V = 5.1 x 10^-6 m^3
Weight of gold = Volume of gold x density of gold x gravity
W' = 5.1 x 10^-6 x 19.32 x 1000 x 9.8 = 0.966 N
As W' is less than W so, it is not pure gold.