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Viktor [21]
3 years ago
13

What is the root mean square speed of an As4 particle as it is sublimed? (Assume at high temperatures arsenic acts like an ideal

gas; the Boltzmann constant, kB, can be approximated as 1.4 x 10-23 J∙K-1) and the kinetic energy of the gas is equal to 3/2kB T
Physics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer: v_{rms} = 273m/s

Explanation: <u>Root</u> <u>Mean</u> <u>Square</u> <u>Speed</u> of an atom or molecule is the speed of a particle in a gas. It is the average speed a particle in a gas can have.

It can be calculated:

\frac{1}{2}mv^{2} = \frac{3}{2} k_{B}T

v^{2} = \frac{3k_{B}T}{m}

v = \sqrt{\frac{3k_{B}T}{m}}

m is mass of one atom or molecule in kg.

An atom of Arsenic sublimes at 614°C. Converting to Kelvin:

T = 614 + 273 = 887K

Molecular mass of As4 is approximately 0.3kg.

m = \frac{0.3}{6.10^{23}}

m=5.10^{-25}kg

Calculating Root mean square speed :

v = \sqrt{\frac{3*1.4.10^{-23}*887}{5.10^{-25}}

v = \sqrt{745.08.10^{2}

v = 273m/s

<u>The root mean square speed of As4 is approximately </u><u>273m/s</u><u>.</u>

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u=0
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