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2 years ago

How is energy transferred and transformed? and examples with full explanation.

1 answer:

7 0

Though it may not always be obvious, energy transfers and transformations constantly happen all around us and are what enable life as we know it to exist. There are three types of thermal energy transfer: conduction, radiation, and convection. Convection is a cyclical process that only occurs in fluids.

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A 11-inch candle is lit and burns at a constant rate of 0.9 inches per hour. Let t t represent the number of hours since the can

Serggg [28]

Answer: F(t) = 11 - 0.9(t)

Explanation:

We know the following:

The candle burns at a ratio given by:

Burning Ratio (Br) = 0.9 inches / hour

The candle is 11 inches long.

To be able to create a function that give us how much on the candle remains after turning it after a time (t). We will need to know how much of the candle have been burned after t.

Let look the following equation:

Br = Candle Inches (D) / Time for the Candle to burn (T) (1)

Where (1) is similar to the Velocity equation:

Velocity (V) = Distance (D)/Time(T)

This because is only a relation between a magnitude and time.

Let search for D on (1)

D = Br*T (2)

Where D is how much candle has been burn in a specif time

To create a function that will tell us how longer remains of the candle after be given a variable time (t) we use the total lenght minus (2):

How much candle remains? ( F(t) ) = 11 inches - Br*t

F(t) = 11 - 0.9(t)

F(t) defines the remaining length of the candle t hours after being lit

8 0

3 years ago

A cube of mass m1=9.6 kgm1=9.6 kg is sitting on top of a second cube of the same size and mass m2=0.8 kgm2=0.8 kg while both are

GalinKa [24]

Answer:N=0

Explanation:

Given

$m_1=9.6 kg$

$m_2=0.8 kg$

both blocks experiencing free fall so net weight of block during free fall is zero thus there is no normal reaction between them.

N=0

8 0

3 years ago

Factors that affect pressure in liquids

Alona [7]

Two factors influence the pressure of fluids. They are the depth of the fluid and its density.

7 0

3 years ago

Read 2 more answers

a 2.0-mole sample of an ideal gas is gently heated at constant temperature 330 k. it expands from initial volume 19 l to final v

shutvik [7]

Isothermal Work = PVln(v₂/v₁)

PV = nRT = 2 mole * 8.314 J/ (k.mol) * 330 k = 5487.24 J

Isothermal Work = PVln(v₂/v₁) v₂ = ? v₁ = 19L,

1.7 kJ = (5487.24)In(v₂/19)

1700 = (5487.24)In(v₂/19)

In(v₂/19) = (1700/5487.24) = 0.3098

In(v₂/19) = 0.3098

(v₂/19) = $e^{0.3098}$

v₂ = 19* $e^{0.3098}$

v₂ = 25.8999

v₂ ≈ 26 L Option b.

6 0

3 years ago

A glass tube 1 mm in diameter is dipped into glycerin. The density of the glycerin is 1260 kg/m3, surface tension is 6.3x10-2 N/

Sunny_sXe [5.5K]

Answer:

The capillary rise of the glycerin is most nearly $y = 0.0204 \ m$