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Ierofanga [76]
3 years ago
11

In Newtons famous event that why, apple always falls to the Earth. Suppose the weight of the apple is 2.5 N. Then calculate the

force that does the apple exert on the Earth and also mention the direction of the calculated force?
Physics
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer:

2.5 N (Centrifugal direction)

Explanation:

According to the Newton's Third Law, there is a reaction when an action exist. The reaction force has the same magnitude but opposite direction. Therefore,  the force that apple exerts on the Earth has a magnitude of 2.5 N and a centrifugal direction.

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A e limb of mass 12kg falls straight down. If air resistance exerts 27 N of froce on the limb as it falls, what is the net force
Gelneren [198K]
During the falling down, two forces are present: gravitational force and air resistance.

So, the net force = mg - f = 12*9.8 - 27 = 90.6 N, the positive sign indicates the direction is pointing towards the center of the earth, which is the same as gravitational force
6 0
2 years ago
Please need help fast
iVinArrow [24]

(a) See graph in attachment

The appropriate graph to draw in this part is a graph of velocity vs time.

In this problem, we have a horse that accelerates from 0 m/s to 15 m/s in 10 s.

Assuming the acceleration of the horse is uniform, it means that the velocity (y-coordinate of the graph) must increase linearly with the time: therefore, the velocity-time graph will appear as a straight line, having the final point at

t = 10 s

v = 15 m/s

(b) 1.5 m/s^2

The average acceleration of the horse can be calculated as:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time interval

In this problem,

u = 0

v = 15 m/s

t = 10 s

Substituting,

a=\frac{15-0}{10}=1.5 m/s^2

(c) 75 m

For a uniformly accelerated motion, the distance travelled can be calculated by using the suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance travelled

u is the initial velocity

t is the time interval

a is the acceleration

In this problem,

u = 0

t = 10 s

a=1.5 m/s^2

Substituting,

s=0+\frac{1}{2}(1.5)(10)^2=75 m

(d) See attached graphs

In a uniformly accelerated motion:

- The distance travelled (x) follows the equation mentioned in part c,

x=ut+\frac{1}{2}at^2

So, we see that this has the form of a parabola: therefore, the graph x vs t will represents a parabola.

- The acceleration is constant during the motion, and its value is

a=1.5 m/s^2 (calculated in part b)

therefore, the graph acceleration vs time will show a flat line at a constant value of 1.5 m/s^2.

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3 years ago
What are the reactants of cellular respiration? Check all that apply. carbon dioxide energy glucose oxygen water
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Answer:

Glucose and Oxygen

Explanation:

Cellular respiration is the process whereby cells derives energy by the use of glucose and oxygen.

Organisms that use cellular respiration to produce their energy are known as heterotophs. They derive the glucose from food materials obtained from plant sources. They use the oxygen from the environment to liberate energy from the glucose obtained from feeding on plant materials.

Cellular respiration can be simply expressed as shown below:

GLUCOSE + OXYGEN → CO₂ + H₂O + ATP

The reactants are glucose and oxygen.

The products are CO₂, water and ATP

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B is the awser 
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