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DaniilM [7]
3 years ago
13

Write the absolute value equations in the form |x−b|=c (where b is a number and c can be either number or (an expression) that h

ave the following solution sets:
Two Solutions: x=2, x=14
Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0

Answer:

  • |x − 8| = 6

Step-by-step explanation:

  • |x − b| = c
  • 1. x - b = c ⇒ x = b + c
  • 2. x - b = -c ⇒ x = b - c

<u>We have solution:</u>

  • b + c = 14
  • b - c = 2

<u>Add up these two equations:</u>

  • 2b = 16
  • b = 8

<u>Find c:</u>

  • c = 8 - 2 = 6

<u>The original equation is:</u>

  • |x − 8| = 6
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-10(2x+1/5) in standard form
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Answer:

-20x-2

Step-by-step explanation:

5 0
2 years ago
The polynomial function y = x3 -3x2 + 16x - 48 has only one non-repeated x-intercept. What do you know about the complex zeros o
earnstyle [38]
• First way to solve:
We'll manipulate the expression of the equation:

y=x^3-3x^2+16x-48\\\\ y=x^2(x-3)+16(x-3)\\\\ y=(x-3)(x^2+16)

If we have y=0:

x-3=0~~~or~~~x^2+16=0\\\\ x=3~~~or~~~x^2=-16\\\\ x=3~~~or~~~x=\pm\sqrt{-16}\\\\ x=3~~~or~~~x=\pm4i

Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).

Answer: B


• Second way to solve:

The degree of the function is 3. So, the function has 3 complex zeros.

Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)

The function "has only one non-repeated x-intercept", then there is only one real zero.

The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.

Answer: B.
3 0
3 years ago
HELP!!
torisob [31]

195 is the answer because you replace x with 10

Step-by-step explanation:

825-630=195

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