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3 years ago

How many times greater is the value of the fidget 2 in 234567 than the value of the digit 2 in 765432

Mathematics

1 answer:

Scilla [17]3 years ago

6 0

Answer:

The value of 2 in the first digit is 100,000 times greater than the value of 2 in the second digit

Step-by-step explanation:

Firstly, we need to know the value of the 2 in 234,567 and that is 200,000

The value of the 2 in 765,432 is simply 2

So the number of times the value of the first 2 is greater than the value of the second 2 is;

200,000/2 = 100,000

So the value of 2 in the first digit is 100,000 times greater than the value of 2 in the second digit

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Find the sum of the even numbers shown below. 2+4+6+8+...+66+68+70

Mandarinka [93]

The sum its +2

2+2=4

4+2=6

6+2=8

8+2=10

And so on the numbers just keep sum for 2

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3 years ago

Pls give me the answer! Thanks!

Mademuasel [1]

Answer:

Step-by-step explanation:

7 x 6 = 42 + 9 = 51 + 54 = 105 + 75= 180

6 0

2 years ago

Read 2 more answers

An amount was shared in the ratio 8:6:9:14:12.The largest share was56.What was the total amount shared?

lutik1710 [3]

Answer:

196

Step-by-step explanation:

Since the largest share was 56 and the largest ratio is 14, then

56 ÷ 14 = 4 ← value of 1 part of the share, thus

8 parts = 8 × 4 = 32

6 parts = 6 × 4 = 24

9 parts = 9 × 4 = 36

14 parts = 14 × 4 = 56

12 parts = 12 × 4 = 48

Total the amounts

total = 32 + 24 + 36 + 56 + 48 = 196

6 0

3 years ago

Use place value pattern to complete the table

svp [43]

Do you have a picture

4 0

3 years ago

3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall

Katen [24]

Answer:

The volume of the toy is $V=5.23\ ft^3$

Step-by-step explanation:

step 1

Find the volume of the hemisphere

The volume of the hemisphere is given by the formula

$V=\frac{2}{3}\pi r^{3}$

In this problem, the wide of the toy is equal to the diameter of the hemisphere

$D=2\ ft$

$r=2/2=1\ ft$ ----> the radius is half the diameter

substitute

$V=\frac{2}{3} \pi (1)^{3}=\frac{2}{3} \pi\ ft^3$

step 2

Find the volume of the cone

The volume of the cone is given by

$V=\frac{1}{3}\pi r^{2}h$

we know that

The radius of the cone is the same that the radius of the hemisphere

$r=1\ ft$

The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy

$h=4-1=3\ ft$

substitute the given values

$V=\frac{1}{3}\pi (1)^{2}(3)=\pi\ ft^3$

step 3

Find the volume of the toy

we know that

The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.

$V=(\frac{2}{3} \pi+\pi)\ ft^3$

$V=(\frac{5}{3}\pi)\ ft^3$

assume

$\pi=3.14$

$V=\frac{5}{3}(3.14)=5.23\ ft^3$

5 0

3 years ago