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Bogdan [553]
3 years ago
14

Semi-conductors are materials that

Physics
2 answers:
mixas84 [53]3 years ago
6 0
You're right, it is C
SVETLANKA909090 [29]3 years ago
4 0
Semi = half ... conductor = conductor so, they're SORT OF half conductors and half insulators ... and that's just the beginning of the story ...
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Which letter indicates X-rays?
ollegr [7]

Answer:

D

Explanation:

The wavelength of A falls in the range of 700 nanometers to 1 millimeter. It is Infra red

The wavelength of B falls in the range of 450 nanometers to 740 nanometers. It is visible light

The wavelength of C falls in the range of 10 nanometers to 400 nanometers. It is Ultraviolet.

The wavelength of D falls in the 0.01 nanometers to 10 nanometers. It is x ray.

6 0
3 years ago
Which of the following statements is true?
Vikki [24]

Answer:

The answer is B.

Explanation:

They are in control of the experiment, they can change it the variables to better help the experiment.

5 0
3 years ago
Read 2 more answers
11. An example of a compound is<br> A. salt<br> B. salt water<br> C. sodium<br> D. soft drinks
katovenus [111]

Answer:

The correct answer is: A. salt

Explanation:

The salt corresponds to sodium chloride, whose chemical formula is NaCl. A compound is defined as that substance formed by a combination of 2 or more atoms.

8 0
3 years ago
How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a po
miss Akunina [59]

Incomplete question as the charge density is missing so I assume charge density of 3.90×10^−12 C/m².The complete one is here.

An electron is released from rest at a distance of 0 m  from a large insulating sheet of charge that has uniform surface charge density 3.90×10^−12 C/m² .  How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 3.00×10−2 m from the sheet?

Answer:

Work=1.06×10⁻²¹J

Explanation:

Given Data

Permittivity of free space ε₀=8.85×10⁻¹²c²/N.m²

Charge density σ=3.90×10⁻¹² C/m²

The electron moves a distance d=3.00×10⁻²m

Electron charge e=-1.6×10⁻¹⁹C

To find

Work done

Solution

The electric field due is sheet is given as

E=σ/2ε₀

E=\frac{3.90*10^{-12}C/m^{2}  }{2(8.85*10^{-12}C^{2} /N.m^{2} )}\\ E=0.22V/m

Now we need to find force on electron

F=eE\\F=(1.6*10^{-19}C )(0.22V/m)\\F=3.525*10^{-20}N

Now for Work done on the electron

W=F*d\\W=(3.525*10^{-20} N)(3.00*10^{-2}m)\\W=1.06*10^{-21}J

4 0
4 years ago
A beam of red light is made to pass through two slits that are 3.55 E-3 meters apart. On a screen 2.25 meters away from the slit
Tom [10]

1.97 E-7 m should be right. I took this a while ago.

6 0
3 years ago
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