The frequency of the signal is = 2.5 Hz
<h3>Calculation of frequency</h3>
The wavelength of the sonar device = 5.9 m
The velocity of the sound = 15 m/s
The frequency = ?
But the formula for the velocity of sound wave = frequency × wavelength
Male frequency the subject of formula,
f = v/ wavelength
f = 15/5.9
f = 2.5Hz
Therefore, the frequency of the signal is = 2.5Hz
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Answer:
The final velocity of the runner at the end of the given time is 2.7 m/s.
Explanation:
Given;
initial velocity of the runner, u = 1.1 m/s
constant acceleration, a = 0.8 m/s²
time of motion, t = 2.0 s
The velocity of the runner at the end of the given time is calculate as;

where;
v is the final velocity of the runner at the end of the given time;
v = 1.1 + (0.8)(2)
v = 2.7 m/s
Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.
Answer:
Directly Proportional
Explanation:
Gravitational force can be calculated with the equation F = g(m1 * m2)/ r^2
So if we increase mass, force will also increase because mass is in the numerator.
Hey!
Given ,
Acceleration, a = 5 m/s^2
time , t = 10 seconds
Initial velocity,u = 0
Final velocity , v = ?
We have ,
v = u + at
=> v = (0)+(5)(10)
=> v = 50 m/s
Answer:
1 N
Explanation:
From coulomb's law,
The force of attraction between two charges is inversely proportional to the square of the distance between the charges.
From the question,
Assuming the charges are the same in both case,
F ∝ /r²....................... Equation 1
Fr² = k
F'r'² = Fr²........................... Equation 2
Where F' = First Force, r'² = First distance, F = second force, r² = second distance.
make F the subject of the equation,
F = F'r'²/r².................... Equation 3
Given: F' = 4 N, r' = 3 m, r = 6 m
Substitute into equation 3
F = 4(3²)/6²
F = 36/36
F = 1 N