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3 years ago

If the length of a ramp is increased, what will happen to the input force?

1 answer:

3 0

The input force will increase too because the more the ramp is increasing the more force is being put on the object going down the ramp... hope this helps ^-^

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A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity i

nydimaria [60]

1. -23.2 J

The gravitational potential energy of the ball is given by

$U=mgh$

where

m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

h is the height of the ball, relative to the reference point chosen

In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J$

2. 41.1 J

Again, the gravitational potential energy of the ball is given by

$U=mgh$

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

$U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J$

3. 0 J

As before, the gravitational potential energy of the ball is given by

$U=mgh$

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J$

4 0

3 years ago

..................,,,,,,,,,

Fiesta28 [93]

Answer:

.....,.,.,.,.,.,.,.,.,.,.,.,..,.,.,.,.,.,.,,.,.┌(・。・)┘♪

7 0

2 years ago

Read 2 more answers

What is the length of the orbit of the earth around the sun?

Rzqust [24]

Answer:

S = 2 π R

R (mean) = 92.9E6 miles

S = 2 * 3.14 * 92.9E6 miles = 5.84E8 miles

5 0

2 years ago

Federal board paper of class 10 of physics

zzz [600]

Answer:

If you are looking for past papers you can search that up and you will find plenty of resources that will help you out.

8 0

3 years ago

A twin-sized air mattress used for camping has dimensions of 100 cm by 194 cm by 14 cm when blown up. The weight of the mattress

Paul [167]

Answer:

$2625.156\ \text{N}$

Explanation:

Dimensions of mattress 100 cm by 194 cm by 14 cm

$m_m$ = Mass of mattress = 4 kg

$\rho$ = Density of water = $1000\ \text{kg/m}^3$

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Volume of mattress

$V=100\times 194\times 14=271600\ \text{cm}^3=0.2716\ \text{m}^3$

Weight of water displaced is equal to the buoyant force

Mass of water

$m=\rho V\\\Rightarrow m=1000\times 0.2716\\\Rightarrow m=271.6\ \text{kg}$

Mass of person would be

$m_p=m-m_m=271.6-4\\\Rightarrow m_p=267.6\ \text{kg}$

Weight of the person would be

$w=m_pg\\\Rightarrow w=267.6\times 9.81\\\Rightarrow w=2625.156\ \text{N}$

The air mattress could hold a person that weighs up to $2625.156\ \text{N}$ .

8 0

2 years ago