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2 years ago

If the length of a ramp is increased, what will happen to the input force?

1 answer:

3 0

The input force will increase too because the more the ramp is increasing the more force is being put on the object going down the ramp... hope this helps ^-^

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Which tools would be use to find an irregularly shaped object’s mass and volume?

madreJ [45]

Scales for weight
Any beaker to measure the volume of liquid displaced

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2 years ago

What is the kinetic energy of a 1700 kg car traveling at a speed of 30 m/s (â65 mph)? does your answer to part b depend on the c

MArishka [77]

The kinetic energy of an object is given by
$K= \frac{1}{2} mv^2$
where m is the mass of the object and v its velocity.

For the car in the problem, $m=1700 kg$ and $v=30 m/s$ , so the kinetic energy of the car is
$K= \frac{1}{2}mv^2= \frac{1}{2}(1700 kg)(30 m/s)^2=7.65\cdot 10^5 J$

and as we can see, yes, the answer depends on the car's mass.

6 0

2 years ago

You are riding your bike to the mall. You travel the first mile in 10 minutes. The last mile takes you 15 minutes. This is an ex

ratelena [41]

I am pretty sure that when you travel the first mile in 10 minutes. The last mile takes you 15 minutes. This is an example of negative acceleration. I consider this to be correct because <span>the second mile was slower. Hope you will agree with me. Regards!</span>

4 0

2 years ago

Read 2 more answers

Chegg Given that the mean radius of the Moon’s orbit is 3.84 x 108 m and its period is 2.36 x 106 sec, at what altitude above th

alukav5142 [94]

Answer:

The altitude of geostationary satellite is $3.58\times10^{7}\ m$

Explanation:

Given that,

Radius of moon's orbit $r=3.84\times10^{8}\ m$

Time period $T=2.36\times10^{6}\ sec$

We need to calculate the orbital radius of geostationary satellite is

Using formula of time period

$T=\sqrt{\dfrac{4\pi^2}{GM}a^3}$

$a=((\dfrac{GM}{4\pi^2})T^2)^{\dfrac{1}{3}}$

Where, G = gravitational constant

M = Mass of earth

T = time period of geostationary satellite orbit

Put the value in to the formula

$a=((\dfrac{6.67\times10^{-11}\times5.97\times10^{24}}{4\times\pi^2})\times(86160)^2)^{\dfrac{1}{3}}$

$a=4.217\times10^{7}\ m$

We need to calculate the altitude of geostationary satellite

Using formula of altitude

$h = a-R_{e}$

Where, R = radius of earth

a = radius of geostationary satellite

Put the value into the formula

$h =4.217\times10^{7}-6.38\times10^{6}$

$h =35790000\ m$

$h=3.58\times10^{7}\ m$

Hence, The altitude of geostationary satellite is $3.58\times10^{7}\ m$

4 0

3 years ago

What are the formulas to calculate acceleration

IRINA_888 [86]

In middle school, the formula you'll use most often when you're
working with acceleration is . . .

Acceleration = (change in speed during some time) / (time for the change)

5 0

2 years ago

Read 2 more answers