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Liula [17]
3 years ago
11

When tension is applied to a metal wire of length L , it stretches by Δ L . If the same tension is applied to a metal wire of th

e same material with the same cross-sectional area but of length 2 L , by how much will it stretch?
Physics
2 answers:
hichkok12 [17]3 years ago
7 0

Answer:

It will stretch by 2ΔL

Explanation:

The young modulus for the metals in both cases is the same as it is a property of the metal.

Y1 = Y2

Tensile force and area in both cases are the same.

Let the unknown increase in length be x.

F/A × L/ΔL = F/A × 2L/x

By canceling out like terms and rearranging, x = 2ΔL.

Anna [14]3 years ago
6 0

Answer:

The metal wire will stretch by 2 \delta L

Explanation:

T = \frac{kA \delta L}{L}......................................(1)

Where T = Tension applied

ΔL = Extension

L = length

k = constant

T₁ = T₂ = T

A₁ = A₂ =A

L₁ = L

L₂ = 2L

(ΔL)₁ = ΔL

(ΔL)₂ = ?

From equation (1)

TL/kA = \delta L.....................(2)

TL/kA = (\delta L) ........................(3)\\ 2TL/kA = (\delta L)_{2} ........................(4)

Divide (4) by (3)

\frac{(\delta L)_{2} }{\delta L} =\frac{\frac{2TL}{kA} }{\frac{TL}{kA} } \\\frac{(\delta L)_{2} }{\delta L} = 2\\ (\delta L)_{2} = 2\delta L

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A race car moving along a circular track has a centripetal acceleration of 15.4 m/s? If the car has
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Answer:

r = 58.44 [m]

Explanation:

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A 100kg crate slides along a floor with a starting velocity of 21ms If the force due to friction is 8N how long will it take for
GaryK [48]

A 100kg crate slides along a floor with a starting velocity of 21 m/s. If the force due to friction is 8N, then, it will take 262.5 s for the box to come to rest.

We'll begin by calculating the declaration of the box. This can be obtained as follow:

Force (F) = –8 N (opposition)

Mass (m) = 100 Kg

<h3>Deceleration (a) =? </h3>

<h3>F = ma</h3>

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Divide both side by 1000

a = \frac{-8}{100}

<h3>a = –0.08 ms¯²</h3>

Therefore, the deceleration of the box is –0.08 ms¯²

Finally, we shall determine the time taken for the box to come to rest. This can be obtained as follow:

Deceleration (a) = –0.08 ms¯²

Initial velocity (u) = 21 ms¯¹

Final velocity (v) = 0 ms¯¹

<h3>Time (t) =.? </h3>

<h3>v = u + at</h3>

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0 = 21 – 0.08t

Collect like terms

0 – 21 = –0.08t

–21 = –0.08t

Divide both side by –0.08

t = \frac{-21}{-0.08}\\\\

<h3>t = 262.5 s</h3>

Therefore, it will take 262.5 s for the box to come to rest.

Learn more: brainly.com/question/14446351

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