When the mass of the cylinder increased by a factor of 3, from 1.0 kg to 3.0 kg, what happened to the cylinder’s gravitational p
2 answers:
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Answer:
x = 5.79 m
Explanation:
given,
mass of the car = 39000 Kg
spring constant = 5.7 x 10⁵ N/m
acceleration due to gravity = 9.8 m/s²
height of the track = 25 m
length of spring compressed = ?
using conservation of energy
potential energy is converted into spring energy
x = 5.79 m
the spring is compressed to x = 5.79 m to stop the car.
1) The equivalent resistance of two resistors in parallel is given by:
so in our problem we have
and the equivalent resistance is
2) If we have a battery of 12 V connected to the circuit, the current in the circuit will be given by Ohm's law, therefore:
so in our problem we have
and the equivalent resistance is
2) If we have a battery of 12 V connected to the circuit, the current in the circuit will be given by Ohm's law, therefore:
Answer:
Explanation:
Given
mass of Flywheel
mass of bus
radius of Flywheel
final speed of bus
Conserving Energy i.e.
0.9(Rotational Energy of Flywheel)= change in Kinetic Energy of bus
Let be the angular velocity of Flywheel