An automobile approaches a barrier at a speed of 20 m/s along a level road. The driver locks the brakes at a distance of 50 m fr
1 answer:
Answer:
μ = 0.408
Explanation:
given,
speed of the automobile (u)= 20 m/s
distance = 50 m
final velocity (v) = 0 m/s
kinetic friction = ?
we know that,
v² = u² + 2 a s
0 = 20² + 2 × a × 50
a = 4 m/s²
We know
F = ma = μN
ma = μ mg
a = μ g
μ = 0.408
hence, Kinetic friction require to stop the automobile before it hit barrier is 0.408
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Answer:
The initial velocity of the softball is 14.711 meters per second.
Explanation:
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(Eq. 1)
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- Initial velocity of the softball, measured in meters per second.
- Time, measured in seconds.
- Gravitational acceleration, measured in meters per square second.
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and
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