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2 years ago

Why does the moon exert a greater tidal influence than the sun?

1 answer:

4 0

Well, I'm not sure right now that it actually does.

But if it does, that's because the sun is about 400 times
FARTHER from the Earth than the moon is.

You might be interested in

During which stage does the birth rate begin to decline?

sveticcg [70]

Answer:

During stage 3 - late expanding (of demogrpahic transition model)

Explanation:

During stage 3, birth rate begins to decline as infant mortality is lower and women have more access to education, family planning, and contraceptives. Children are not needed as "free labor" as they might have been in earlier stages.

3 0

3 years ago

Read 2 more answers

Four students made a graphic organizer describing the parts of the atom.

Nikitich [7]

Answer:

I believe the answer is D.

Explanation:

Protons are found inside the nucleus so are neutrons. Electrons are found outside the nucleus.

8 0

2 years ago

Read 2 more answers

If it requires 7.0 j of work to stretch a particular spring by 2.1 cm from its equilibrium length, how much more work will be re

SVEN [57.7K]

4.6 j more. To get this take 7 and multiply it by 3.5 to get 24.5 take the x which is what you’re looking for and multiply it by the 2.1 to get 2.1x. Take 24.5 and divide it by 2.1 x and get 11.6. Subtract 11.6 by 7 and get 4.6

8 0

2 years ago

A vertical cylindrical tank 10 ft in diameter, has an inflow line of 0.3 ft inside diameter and an outflow line of 0.4 ft inside

neonofarm [45]

Answer:

$\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}$ , level is rising.

Explanation:

Since liquid water is a incompresible fluid, density can be eliminated of the equation of Mass Conservation, which is simplified as follows:

$\dot V_{in} - \dot V_{out} = \frac{dV_{tank}}{dt}$

$\frac{\pi}{4}\cdot D_{in}^2 \cdot v_{in}-\frac{\pi}{4}\cdot D_{out}^2 \cdot v_{out}= \frac{\pi}{4}\cdot D_{tank}^{2} \cdot \frac{dh}{dt} \\D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out} = D_{tank}^{2} \cdot \frac{dh}{dt} \\\frac{dh}{dt} = \frac{D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out}}{D_{tank}^{2}}$

By replacing all known variables:

$\frac{dh}{dt} = \frac{(0.3 ft)^{2}\cdot (5 \frac{ft}{s} ) - (0.4 ft)^{2} \cdot (2 \frac{ft}{s} )}{(10 ft)^{2}}\\\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}$

The positive sign of the rate of change of the tank level indicates a rising behaviour.

6 0

3 years ago

In a series rlc ac circuit, a second resistor is connected in parallel with the resistor previously in the circuit. as a result

raketka [301]

According to the given statement:

The frequency response does not change, which is the first thing we notice.

The new resistance at the resonance point causes a reduction in the circuit's current flow.
Z = R + R₂

<h3>The definition of series circuits:</h3>

electrical circuit. The path that the entire current takes as it passes through each component makes up a series circuit. Branching is used in parallel circuits to divide the current and limit the amount that flows through each branch.

<h3>How does a series circuit operate?</h3>

According to this definition, there are three principles of series circuits: all parts share the same current, resistances add up to a larger total resistance, and voltage drops add up to a larger total voltage. In the definition of a series circuit, all of these guidelines have their origin.

<h3>According to the given information:</h3>

The impedance of a series circuit is

Z₀² = R² + (X $_L$ -X $_C$ ) ²

The initial resistance impedance shifts to when we add another resistor to the series

Z² = (R + R₂) ² + (X $_L$ - X $_C$ ) ²

Let's examine this sentence.

The frequency response remains unchanged, which is the first thing we notice.
The new resistance at the resonance point causes the circuit's current to decrease.

Z = R + R₂

To know more about electrical circuit visit:

brainly.com/question/1922668

#SPJ4

6 0

1 year ago