Using kinematic equation, v^2 - u^2 = 2as. 5^2 - 3^2 = 2a x 16. a = 0.5m/s^2. So particle will deaccelerate at 0.5m/s^2. ( v = final velocity, u= initial velocity, a= acceleration, s= displacement.)
Answer:
After 15 seconds, the green car will catch up with the blue car
Explanation:
Let the time for the green car to catch up with the blue car be T
When the green car catches up to the blue car, the distances covered by each car after time T will be equal. Also, their velocities at that instant will be equal
Distance covered by blue car after time T is given by: s = ut + 0.5 at²
Where u = 0, a = 0.2 m/s², t = T
S = 0.5 × 0.2 × T² = 0.1 T²
Velocity of blue car, v = u+ at
v = 0.2T
Distance covered by green car at T is given as: S = Velocity × time
Where v = 0.2T, t = T - 7.5 (since the blue car started 7.5 seconds earlier)
S = 0.2T (T - 7.5)
S = 0.2 T² - 1.5T
Equating the distance covered by the two cars
0.2T² - 1.5T = 0.1T²
0.1T² - 1.5T = 0
T(0.1T - 1.5) = 0
T = 0 or
T = 1.5/0.1 = 15 secs
Therefore, after 15 seconds, the green car will catch up with the blue car
Answer:
In a tennis match, the racket exerts the action force on the ball and, as the ball hits it, it exerts an equal and opposite reaction force on the racket. The rocket launches because it pushes on the gas coming out the back end for the action force, while the gas pushes the rocket upward with a reaction force.
Answer:
Explanation:
2.5 g of He = 2.5 / 4 mole
= .625 moles
9 g of oxygen = 9/32
= .28 mole of oxygen
C_p of He = 3/2 R
C_p of O₂ = 5/2 R
A ) Initial thermal energy of He = 3/2 n R T
= 1.5 x .625 x 8.32 x 300
= 2340 J
Initial thermal energy of O₂ = 5/2 n R T
= 2.5 x .28 x 8.32 x 620
= 3610.88 J
B ) If T be the equilibrium temperature after mixing
gain of heat by helium
= n C_p Δ T
= .625 x 3/2 R x ( T - 300 )
Loss of heat by oxygen
n C_p Δ T
= .28 x 5/2 R x ( 620 - T )
Loss of heat = gain of heat
.625 x 3/2 R x ( T - 300 ) = .28 x 5/2 R x ( 620 - T )
1.875 T- 562.5 = 868- 1.4 T
3.275 T = 1430,5
T = 436.8 K
Thermal energy of He
= 1.5 x .625 x 8.32 x 436.8
= 3407 J
thermal energy of O₂
= 2.5 x .28 x 8.32 x 436.8
= 2543.92 J
C )
Heat energy transferred
= .28 x 5/2 R x ( 620 - T )
= .28 x 5/2 x 8.32 x ( 620 - 436.8 )
1066.95 J
Heat will flow from O₂ to He
Final temperature is 436.8 K
Any type of wetland that has been developed or maintained by humans for uses such as aquaculture, irrigation, or water storage.
<h3>What is a human-made wetland ?</h3>
Any kind of wetland that has been created or kept up by people for purposes like water storage, irrigation, or aquaculture.
In India's Punjab state, in the Kapurthala district, lies the man-made Kanji Wetland, which includes the Kanji Lake.
In order to give irrigation facilities to the hinterland, it was built by building the headworks over the perennial Bien River, a tributary of the Beas River.
The Sunderbans are India's biggest wetland. The world's biggest mangrove forest includes Sunderban Wetland.
Hence, the human-made wetland is an artificial wetland.
To learn more about the human-made wetland refer;
brainly.com/question/1334452
#SPJ1
