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AleksandrR [38]
3 years ago
8

Imagine that you have two marbles on a table. You roll one marbles towards another. When the marble collide, the marble at rest

begins to roll. What do you think cause the second marble to move? What do you think because the marble to stop rolling?
Physics
1 answer:
Alika [10]3 years ago
8 0

Because that's called friction. When to things collide it causes friction which makes them stop rolling>

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What would the scale read? zero

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Roller coasters are for fun seekers. NASA is for science

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A car is moving 18 m/s to the east. if it takes the car 5 seconds to reach a velocity of 19 m/s to the east, what is its acceler
almond37 [142]
<span>C. 0.2 m/s2 east

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Calculate the Earth's linear momentum, in kilogram meters per second.
Irina18 [472]
The sun orbits the eth at 2kilogram per sec
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3 years ago
The planet Mars has a mass of 6.1 × 1023 kg and radius of 3.4 × 106 m. What is the acceleration of an object in free fall near t
Oksanka [162]

The acceleration due to gravity of Mars is 3.5\ m / s^{2}

<u>Explanation:</u>

As per universal law of gravity, the gravitational force is directly proportional to the product of masses and inversely proportional to the square of the distance between them. But in the present case, the gravity need to be determined between Mars and the object on Mars. Since the mass of Mars is greater than the mass of any object. Thus,

      \text {Gravitational force of planet}=\frac{G M m}{R^{2}}

Here, G is the gravitational constant, R is the radius of Mars and M, m is the mass of Mars and the object respectively..

Also, according to Newton’s second law of motion, the acceleration of any object will be equal to the ratio of force exerted on it to the mass of the object.

So in order to determine the acceleration due to gravity of Mars, divide the gravitational force of Mars by mass of object on the surface of Mars.

   Acceleration\ due\ to\ gravity\ of\ mars =\frac{\text {Gravitational force of Mars}}{m \text { of object }}

  Acceleration\ due\ to\ gravity\ of\ mars =\frac{G M m}{R^{2} \times m}=\frac{G M}{R^{2}}

  \text { Acceleration due to gravity of mars }=\frac{6.67259 \times 10^{-11} \times 6.1 \times 10^{23}}{3.4 \times 3.4 \times 10^{12}}=\frac{40.703 \times 10^{12}}{11.56 \times 10^{12}}

 \text { Acceleration }=3.5\ \mathrm{m} / \mathrm{s}^{2}

3 0
3 years ago
A car is going 8 meters per second on an access road into a highway
TiliK225 [7]

Answer:

20.96 m/s^2 (or 21)

Explanation:

Using the formula (final velocity - initial velocity)/time = acceleration, we can plug in values and manipulate the problem to give us the answer.

At first, we know a car is going 8 m/s, that is its initial velocity.

Then, we know the acceleration, which is 1.8 m/s/s

We also know the time, 7.2 second.

Plugging all of these values in shows us that we need to solve for final velocity. We can do so by manipulating the formula.

(final velocity - initial velocity) = time * acceleration

final velocity = time*acceleration + initial velocity

After plugging the found values in, we get 20.96 m/s/s, or 21 m/s

3 0
3 years ago
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