Potential energy is measured using formula Ep=mgh
m=mass (kg)
g= acceleration due to gravity (which is 9.8 on earth)
h= height in metres above ground
For this question
m=0.1
g=9.8
h=1
So Ep=0.1(9.8)(1)
Ep=0.98 Joules
When it is dropped all of this potential energy is converted into kinetic energy which can be measured using formula
Ek=1/2m(v^2) (v=final velocity)
Since all potential energy in this q is converted to kinetic we know Ek=0.98Joules and our mass is the same (0.1kg)
So when we sub everything in we get
0.98=1/2(0.1)(v^2)
0.98=0.05(v^2)||divide both side by 0.05
19.6=v^2 ||square root both sides
v=4.4 m/s
to make sure the argument is true and correct backed up by logic.
Trigonometry allows finding the result for the decomposition of the displacement vector is:
x = 2.12 mi
y = -2.12 mi
Displacement is a vector quantity, which has modulus and direction.
The cardinal points are a reference system with respect to which measurements are made, this system is related to the Cartesian system with the East in the positive direction of the x-axis and the North with the positive direction of the y-axis.
In the attached we can see a diagram of the vector and its components, the indicated direction of 45 S of the E, in the Cartesian system where the angles are measured from the positive side of the x-axis in a counterclockwise direction is:
θ = 360 - 45
θ = 315º
Let's use trigonometry to decompose the vector d = 3 mi
cos 315 =
sin 315 =
x = d cos 315
y = d sin 315
Let's calculate
x = 3 cos 315
y = 3 sin 315
x = 2.12 mi
y = -2.12 mi
The negative sign indicates that the displacement is towards the negative side, that is, towards the South.
In conclusion using trigonometry we can find the result for the decomposition of the displacement vector are:
x = 2.12 mi
y = -2.12 mi
Learn more here: brainly.com/question/1666179
Answer:
116 N.
Explanation:
Given,
mass of the ball, m = 0.145 Kg
initial speed = 0 m/s
Final speed = 40 m/s
time = 50 ms = 0.05 s
Force is equal to change in momentum per unit time
F = 116 N
Force of the pitcher hand on the ball is equal to 116 N.