2 years ago

Find the equation in general form of the circle with center at the origin and radius equal 6.

1 answer:

3 0

$\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&0&0&6
\end{array}\\\\
-------------------------------\\\\
(x-0)^2+(y-0)^2=6^2\implies x^2+y^2=36$

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