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3 years ago

What is the ratio between the mass of nitrogen and oxygen in N2O3?

Chemistry

1 answer:

Ket [755]3 years ago

6 0

Answer:

12:7

Explanation:

To Determine: To calculate the formula of the unknown binary compound of oxygen and nitrogen and to ratio in the next compound of the series using given data.Answer:The formula of the unknown compound .The ratio for atoms of oxygen to nitrogen inis .The mass ratio of oxygen to nitrogen in next member of the series of compounds is .Explanation:The mass ratio of toinis .The mass ratio of toin theunknown compound is .The atomic mass of the oxygen is .The atomic mass of the nitrogen is .The mass ratio of to in a molecule can be represented as: …… (1)Here,is the number of atoms of the oxygen in the molecule.is the mass of an atom of oxygen.is the number of atoms of the nitrogen in the molecule.is the mass of an atom of nitrogen.For unknown compound, substitutefor , for and for mass ratio in equation (1).The ratio of atoms of oxygen to nitrogen is , therefore, the expected formulas of the unknown compound is and . If the unknown compound is in a series with then the formula of the unknown compound and the formula for the next member of the series is .The ratio for atoms of oxygen to nitrogen inis .For , substitute 5 for , for , 2 for and for in equation (1).The mass ratio of oxygen to nitrogen in next member of the series of the compounds is .

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The higher the specific heat, the longer it will take to get hot. The coolest location for Vicente to be would be the water, because its specific heat is higher than the other locations.

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2 years ago

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Each of the following reactions is allowed to reach equilibrium in a sealed container. For which of the reactions could you shif

natta225 [31]

Answer:

None of the reaction will be favored to the right by a decrease in pressure.

Explanation:

CH₄(g) + 2O₂(g) ⇄ CO₂(g) + 2H₂O(l)

CaCO₃(s) ⇄ CaO(s) + CO₂(g)

Br₂(g) + 3Cl₂(g) ⇄ 2BrCl₃(g)

2H₂S(g) + 3O₂(g) ⇄ 2SO₂(g) + 2H₂O(g)

From Le Chatellier's principle, we must understand that pressure changes only affects reactions in gaseous phases. The second reaction will not be affected by pressure.

We are now left with three equations.

Also, increase in pressure favors sides with lower volume. We can know the volume from the coefficients in the equation. Now let us check the volumes:

CH₄(g) + 2O₂(g) ⇄ CO₂(g) + 2H₂O(l)

3 moles of gases 3 moles of gases

Br₂(g) + 3Cl₂(g) ⇄ 2BrCl₃(g)

4 moles of gases 2 moles of gases

2H₂S(g) + 3O₂(g) ⇄ 2SO₂(g) + 2H₂O(g)

5 moles of gases 4 moles of gases

None of the reaction will be favored to the right by a decrease in pressure.

The first reaction will not be affected by any change in pressure because the total number of moles on the two sides are equal.

The last two reactions will be favored to the right by increasing pressure and a decrease in pressure will favor the backward left reaction.

7 0

3 years ago

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g A microwave oven heats by radiating food with microwave radiation, which is absorbed by the food and converted to heat. If the

Sliva [168]

Answer:

The total photons required = 5.19 × 10²⁸ photons

Explanation:

Given that:

the radiation wavelength λ= 12.5 cm = 0.125 m

Volume of the container = 0.250 L = 250 mL

The density of water = 1 g/mL

Density = mass /volume

Mass = Volume × Density

Thus; the mass of the water = 250 mL × 1 g/mL

the mass of the water = 250 g

the specific heat of water s = 4.18 J/g° C

the initial temperature $T_1$ = 20.0° C

the final temperature $T_2$ = 99° C

Change in temperature $\Delta T$ = (99-20)° C = 79 ° C

The heat q absorbed during the process = ms $\Delta T$

The heat q absorbed during the process = 250 g × 4.18 J/g° C × 79° C

The heat q absorbed during the process = 82555 J

The energy of a photon can be represented by the equation :

= hc/λ

where;

h = planck's constant = $6.626 \times 10^{-34} \ J.s$

c = velocity of light = $3.0 \times 10^8 \ m/s$

= $\dfrac{6.626 \times 10^{-34} \times 3.0 \times 10^8}{0.125}$

= $1.59024 \times 10^{-24}$ J

The total photons required = Total heat energy/ Energy of a photon

The total photons required = $\dfrac{82555 J}{1.59024 \times 10^{-24}J}$

The total photons required = 5.19 × 10²⁸ photons

5 0

2 years ago

Please answer 11 and 12, I'm not sure of my answers and I'm gonna be tested on this tomorrow. Thanks!

Novay_Z [31]

11. I would say physical because the color of the item is changed and the texture and density is changed aswell.

8 0

3 years ago

A rectangular block of solid carbon (graphite) floats at the interface of two immiscible liquids.

Sergio039 [100]

Explanation:

Let us take the volume of block is x.

Since, the block is floating this means that it is in equilibrium. Formula to calculate net force will be as follows.

$F_{net} = Buoyancy force(F_{b}) - weight force(w)$

Also, buoyancy force $(F_{b})$ = (volume submerged in water × density of water) + (volume in oil × density of oil)

$(F_{b})$ = $(0.592 V \times \rho) + (1 - 0.592)V \times 1000 g$

= $(0.592 V \times \rho + 408 V)$ g

As, W = V × density of graphite × g

It is given that density of graphite is $2.16 g/cm^{3}$ or 2160 $kg/m^{3}$ .

So, W = 2160 V g

$F_{net}$ = (0.592 V \rho + 408 V) g - 2160 V g = 0

$0.592 \rho$ = 1752

$\rho$ = 2959.46 $kg/m^{3}$ or 2.959 $g/cm^{3}$ is the density of oil.

It is given that mass of flask is 124.8 g.

Mass of 35.3 $cm^{3}$ oil = $35.3 \times 2.959$ 104.7 g

Hence, in second weighing total mass will be calculated as follows.

(124.8 + 104.7) g

= 229.27 g

Thus, we can conclude that in the second weighing mass is 229.27 g.

5 0

2 years ago