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2 years ago

What are the characteristics of nonvascular plants? (select all that apply) A . They don’t rely on roots to receive water.

Chemistry

1 answer:

RUDIKE [14]2 years ago

4 0

Answer:

D . They are found in moist environments.

Explanation:

Nonvascular plants do not have a xylem or phloem, roots, stems, or leaves. Because these plants lack water-conducting tissues, they fail to achieve the structural complexity and size of most vascular plants and have evolved in habitats which allow their survival and reproduction.

The plant body that is most obvious in non-vascular plants are the the gametophyte generation. The gametophte gemeration is haploid.

The non-vascular plants grow in moist environments. It is due to lack of vascular tissue that requires to maintain close contact with water to prevent desiccation. Nonvascular plants are plants that do not have any special internal pipelines or channels to carry water and nutrients. Instead, nonvascular plants absorb water and minerals directly through their leaflike scales. Nonvascular plants are usually found growing close to the ground in damp, moist places. Non-vascular plants thrive in damp conditions since they don't need to rely on roots to acquire enough water.

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Calculate the change in entropy if Br2(l) is converted to Br2(g).

Alik [6]

Ans: The entropy change for the given reaction is 93.3 J/K

Given reaction:

Br2(l) → Br2(g)

ΔS = ∑n(products)S⁰(products) - ∑n(reactants)S⁰(reactants)

= 1 mole* S°(Br2(g)) - 1 mole*S°(Br2(l))

= 1 mole *245.5 J/mol-K - 1 mole*152.2 J/mol-K

= 93.3 J/K

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3 years ago

A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio

brilliants [131]

Explanation:

The given data is as follows.

Concentration of standard NaOH solution = 0.1922 M

Let the original acid solution concentration be x.

$M_{1}V_{1} = M_{2}V_{2}$

$x \times 25 = 250 \times M_{2}$

$M_{2} = \frac{x \times 25}{250}$

= 0.1 x M

$V_{2}$ = 10.00 mL (given)

The reaction equation is as follows.

$2NaOH + H_{2}SO_{4} \rightarrow Na_{2}SO_{4} + 2H_{2}O$

Concentration × Volume of $H_{2}SO_{4}$ = Concentration × Volume of NaOH

$\frac{M_{2}V_{2}}{n_{2}} = \frac{M_{3}V_{3}}{n_{3}}$

$\frac{0.1 x \times 10 ml}{1} = \frac{0.1922 M \times 13.68 ml}{2}$

x = 1.314 M

Therefore, we can conclude that the concentration of the original sulfuric acid solution is 1.314 M.

7 0

3 years ago

Please answer this and explain why :)

pav-90 [236]

Answer: i would have to say c

Explanation:

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3 years ago

Which of the following processes are endothermic? ice forming on a pond iodine crystals subliming water boiling gasoline burning

san4es73 [151]

The boiling of water and sublimation of iodine crystals are endothermic processes.

Answer: Option B & C

Explanation:

Endothermic process are the classifications of chemical reactions where the heat is absorbed by the system from the surroundings. As the matters can exists in three phases like solid, liquid and gases.

The endothermic process occurs by absorption of heat energy by the system. So according to the given options, the boiling of water and iodine crystal sublimation follows endothermic process. In the boiling of water occurs when the water molecules absorb heat from the surrounding and convert to gas phase.

Similarly, the sublimation of iodine crystals also require heat energy from the surrounding to break the bonds of the iodine crystals to sublimate to gas phase. Thus the boiling of water and sublimation of iodine crystals are the examples of endothermic processes.

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3 years ago

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