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maks197457 [2]
3 years ago
13

A board has a mass of 750 g. If you ground the whole board down to sawdust, what would be the mass of the pile of sawdust?

Chemistry
2 answers:
babymother [125]3 years ago
8 0

The answer is 750 grams


ElenaW [278]3 years ago
7 0

The correct answer is exactly 750 g.

Since the mass of board is 750 g, the mass of the pile of sawdust after the whole board is ground down is 750 g.

This is according to the Law of conservation of mass. According to this law, matter can neither be created nor destroyed by any  physical transformations or chemical reactions. In any chemical reaction the mass of the products is equal to the mass of the reactants.

Here the board undergoes a physical transformations from being a whole board to a pile of sawdust. Thus according to the Law of conservation of mass, the mass of the whole board will be equal to the mass of a pile of sawdust.


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N2(g) + 3H2(g) ⟶2NH3(g)

Both equal amount of atoms side to side.

  • Now we verify which reagent is the limiting one by comparing the amount of product formed with each reactant, and the one with the lowest number is the limiting reactant. ( Keep in mind that we use the  molecular weight of 28.01 g/mol N2; 2.02 g/mol H2; 17.03g/mol NH3)

Moles of ammonia produced with 163.3g N2(g) ⟶ 163.3g N2(g) x (1mol N2(g)/ 28.01 g N2(g) )x (2 mol NH3(g) /1 mol N2(g)) = 11.66 mol NH3

Moles of ammonia produced with 38.77 g H2⟶  38.77 g H2 x ( 1mol H2/ 2.02 g H2 ) x (2 mol NH3 /3 mol H2 ) = 12.79 mol NH3

  • As we can see the amount of NH3 formed with the N2 is the lowest one , therefore the limiting reactant is the N2 that means, N2 is the element  that would be completey consumed, and the maximum mass of ammonia will be produced from it.
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11.66  mol NH3 x (17.03 g NH3 /1mol NH3) = 198.57 g NH3

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That means that only 35.33 g H2 will react with 163.3g N2 however we were giving 38.77g of  H2, thus, 38.77g - 35.33 g = 3.44g H2 is left

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