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3 years ago

9

Which answer below correctly identifies the type of change and the explanation for the boiling of water?

2 answers:

lesantik [10]3 years ago

7 0

Boiling Water is a physical change. When water gets to a certain temperature, it's boiling point starts.

Vesnalui [34]3 years ago

6 0

Boiling is when a liquid is being converted to a gas. but the ending product is still the same molecule. in other words, when you boil water to become vapor, the liquid before was liquid water (H2O) and the vapor after is still a water but now in a gaseous state. because the molecule is the same, we can say that boiling is a physical change.

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What type of reaction is shown below? Check all that apply. Ca + 2H2O → Ca(OH)2 + H2 synthesis decomposition combustion single r

Ksju [112]

The balanced reaction is

Ca + 2H2O → Ca(OH)2 + H2

Here this reaction can be compared with

A + BC ---> AB + C

So here one reactant (A) is accepting a group which is being given by another compound (BC) however the A is not giving any group / element or ion

So this single displacement

Similarly in the given reaction

the anion OH- is only being replaced

The element Ca accepts OH- and H2O loses the same group to form new element H2

So the correct answer is

Single replacement also known as single displacement

3 0

3 years ago

Read 2 more answers

Why were foreigners allowed to hold office for the Mongols

Slav-nsk [51]

They shots sides stoned found six end

6 0

3 years ago

nydimaria [60]

Is the answer Radiation

4 0

2 years ago

30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr

Alenkasestr [34]

Answer: Thus concentration of $Ca(OH)_2$ in $mol/dm^3$ is 0.011 and in $g/dm^3$ is 0.814

Explanation:

To calculate the concentration of $Ca(OH)_2$ , we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3$ $1cm^3=0.001dm^3$

Putting values in above equation, we get:

$1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3$

The concentration in $g/dm^3$ is $0.011mol/dm^3\times 74g/mol=0.814g/dm^3$

Thus concentration of $Ca(OH)_2$ is $0.011mol/dm^3$ and $0.814g/dm^3$

4 0

3 years ago

The electron configuration belonging to the atom with the highest second ionization energy is ________.

Gemiola [76]

Answer:

Element Lithium

Explanation:

The element with the highest second ionization energy is lithium. It belongs to the alkaline metal group I.e group one metals

It has the highest second ionization energy because it is very difficult to remove the electron from the 1s orbital.

Its atomic number is 3. The electronic configuration is 1s2 2S1

5 0

3 years ago