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Darya [45]
4 years ago
11

The height, s, of a ball thrown straight down with initial speed 64 ft/sec from a cliff 80 feet high is s(t) = â16t2 â 64t + 80,

where t is the time elapsed that the ball is in the air. what is the instantaneous velocity of the ball when it hits the ground?
Physics
1 answer:
mestny [16]4 years ago
8 0
The height of the ball (ft), measured upward from the ground is
s(t) = 16t² + 64t + 80
where t = time when the ball is in the air.

When the ball hits the ground, s = 0. The time(s) when this occurs is given by
16t² + 64t + 80 = 0
Divide through by 16.
t² + 4t + 5 = 0
(t - 1)(t + 5) = 0
t = 1 or t = -5 s
Reject negative time, so that
t = 1 s

The velocity function is
v(t) = 64 + 32t
When t = 1 s, obtain
v(1) = 96 ft/s

Answer:
The ball hits the ground with velocity 96 ft/s.
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3 years ago
Two train whistles have identical frequencies of 1.85 102 Hz. When one train is at rest in the station and the other is moving n
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Answer:

Explanation:

frequency of whistle = 1.85 x 10² = 185 Hz

frequency of beat heard = 8 beat /s . No of beat produced is equal to difference of frequencies of two sound source . Here difference is created due to Doppler effect . One of the train is moving so it will have apparent frequency which is different one from its original frequency .

When the moving train is approaching the observer , its frequency will be higher . As beat is heard at the rate of 8 beats / s , apparent frequency of approaching train will be 185 + 8 = 193 Hz .

Applying Doppler's formula of apparent frequency ,

193 = 185 x V / ( V - v ) , where V is velocity of sound and v is velocity of train .

193 V - 193 v = 185 V

193 v = 8 V

v = 8 x V / 193

= 8 x 343 / 193

= 14.21 m /s

Second possibility is that apparent velocity is less ie 185 - 8 = 177 Hz

In that case moving train will be moving away from observer . If its velocity be v

177 = 185 x V / ( V + v )

177 V + 177 v = 185 V

v = 8 x 343 / 177

= 15.50 m /s .

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Which of the following describes swinging a bat
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Question 4 Unsaved If element X has 93 protons, how many electrons does it have? Your Answer:
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Solve the following two equations for the (positive) time, t, and the position, x. Assume SI units.
Luden [163]

A system of equations is a group of equations with the same variables that we need to solve simultaneously. Such that the solutions is given by the intersection betweens graphs of the functions.

We will see that the solution is (16.4, 807.0)

Here the system is:

x = 3.00*t^2\\x = 45.0*t + 69.0

To solve a system we usually need to isolate one of the variables in one equation and replace that in the other equation, here we already see that we have x isolated in the two equations, so we can write:

3.00*t^2 = x = 45.0*t + 69.0\\3.00*t^2 = 45.0*t + 69.0

Now we can solve the above equation for t:

3.00*t^2 = 45.0*t + 69.0\\\\3.00*t^2 - 45.0*t - 69.0 = 0

This is just a quadratic equation, the solution is given by the Bhaskara's formula, we will get:

t = \frac{-(-45.0) \pm \sqrt{(-45.0)^2 - 4*(3.00)*(-69.0)} }{2*3.00} \\\\t = \frac{{(45.0) \pm 53.4} }{6.00}

Then the two values of t are:

t = (45.0 + 53.4)/6 = 16.4

t = (45.0 - 53.4)/6 = -1.4

We want the positive solution, so we choose t = 16.4

To complete the solution we need to evaluate one of our functions in this time. Let's use the first one:

x = 45.0*16.4 + 69.0 = 807.0

Then the solution is:

(16.4, 807.0)

If you want to learn more you can read:

brainly.com/question/12895249

5 0
3 years ago
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