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2 years ago

If a 340 g ball has 2.4 J of kinetic energy, what is it's velocity?

Physics

2 answers:

Leno4ka [110]2 years ago

6 0

Answer:

Explanation:

i really dont know im a 4th grader

sergiy2304 [10]2 years ago

4 0

Answer:

3.76

Explanation:

KE = 1/2 * m *v^2

v= $\sqrt{2.4*2/340 *1000}$

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Which electromagnetic wave has the highest frequency

Deffense [45]

Answer:

Gamma rays

Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies.

6 0

2 years ago

Read 2 more answers

10. A force F S 1 of magnitude 6.00 units acts on an object at the ori- gin in a direction u 5 30.0° above the positive x axis (

MArishka [77]

Answer:

The x component of the x axis is: $F_x = F_1\cos(30)=5\cos(30)= 4.33 u$

The y component of the y axis is: $F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u$

The magnitude is given by: $F = \sqrt{F_x+F_y}= 9.54 u$

The direction is given by: $\theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ$

See the graphical magnitude and direction below.

Explanation:

The x component of the x axis is: $F_x = F_1\cos(30)=5\cos(30)= 4.33 u$

The y component of the y axis is: $F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u$

The magnitude is given by: $F = \sqrt{F_x+F_y}= 9.54 u$

The direction is given by: $\theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ$

8 0

2 years ago

Problem 9: Suppose you wanted to charge an initially uncharged 85 pF capacitor through a 75 MΩ resistor to 90.0% of its final vo

Bingel [31]

Answer:

$t=14.678\times 10^{-3}s$

Explanation:

Given:

Capacitance, C = 85 pF = 85 × 10⁻¹² F

Resistance, R = 75 MΩ = 75×10⁶Ω

Charge in capacitor at any time 't' is given as:

$Q=Q_o(1-e^{-\frac{t}{RC}})$

where,

Q₀ = Maximum charge = CE

E = Initial voltage

t = time

also, Q = CV

V= Final voltage = 90% of E = 0.9E

thus, we have

$C\times 0.9E=CE(1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})$

$0.9=1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}$

$e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}=1-0.9=0.1$

taking log both sides, we get

$ln(e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})=ln(0.1)=ln(\frac{1}{10})$

$-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}=-ln(10)$

$t=75\times 10^6\ \times\ 85\times 10^{-12}\times ln{10}$

$t=14.678\times 10^{-3}s$

3 0

3 years ago

At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1400 kg car traveling at 6

Ilia_Sergeevich [38]

Momentum of car

Given: Mass m= 1,400 Kg; V = 6.0 m/s

Formula: P = mv

P = (1,400 Kg)(6.0 m/s)

P = 8,400 Kg.m/s

Velocity of the rider to have the same momentum as a car.

Mass of rider and bicycle m = 100 Kg

P = mv

V = P/m

V = 8,400 Kg.m/s/100 Kg

V = 84 m/s

7 0

2 years ago

What is an example of a form of friction that impedes motion

Travka [436]

Answer:

to me I think is static

Explanation:

that is my own thinking

4 0

2 years ago